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3 years ago

If (a, -5) is a solution to the equation 3a = -2B - 7, what is a?

Mathematics

1 answer:

Andrew [12]3 years ago

3 0

I think what you need to do is make B = -5
3a = -2(-5) - 7
3a = 10 - 7
3a = 3
a = 1

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Solve by substitution or elimination<br> 4X – 3y = 7<br> 4x + y = 11

Simora [160]

Answer:

(5/2 , 1)

Step-by-step explanation:

4X – 3y = 7

4x + y = 11

———————

Multiply a -1 to the bottom equation to get the 4x as a negative so it cancels out.

4x - 3y = 7

-4x - y = -11

——————

-4y = -4

Divide by -4

y = 1

Substitute the value of y into one of the equations and solve

4x - 3(1) = 7

4x -3 = 7

4x = 10

Divide by 4

X = 10/4

Simplify by dividing by 2

x = 5/2

Therefore the answer is (5/2, 1 )

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3 years ago

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Answer:

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Step-by-step explanation:

Just divide -7 by 0.5

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3 years ago

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borishaifa [10]

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Step-by-step explanation:

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3 years ago

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.