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3 years ago

5

Billy likes to go cycling.

2 answers:

denis23 [38]3 years ago

6 0

The circumference is π.d
C=π.d
C=π.(0.70m)=2.20m

270 revolutions x (2.20m)/(1revolution) = 593.76 m
Solution 594 approx.

Maksim231197 [3]3 years ago

4 0

<span><span>aha gülüyor ...............</span>
</span>

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The Garden Task

Igoryamba

If the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

<em><u>Recall</u></em>:

A square has equal side lengths
Perimeter of a square = 4(side length)
Area of a square = $(side $ length)^2$

<em><u>Given:</u></em>

Perimeter of square (P) = $(14x - 32) $ ft$

Side length (s) = $(x + 2) $ ft$

<em><u>First, let's find the </u></em><em><u>value of x</u></em><em><u> by creating an </u></em><em><u>equation </u></em><em><u>using the </u></em><em><u>perimeter </u></em><em><u>formula:</u></em>

Perimeter of a square = 4(side length)

Plug in the values

$(14x - 32) = 4(x + 2)$

Solve for x

$14x - 32 = 4x + 8\\\\14x - 4x = 32 + 8\\\\10x = 40\\\\x = 4$

<em><u>Find how much fencing would be needed (</u></em><em><u>Perimeter </u></em><em><u>of the fence):</u></em>

Perimeter of the fence = $(14x - 32) $ ft$

Plug in the value of x

Perimeter of the fence = $14(4) - 32 = 24 $ ft$

<em><u>Find the </u></em><em><u>area </u></em><em><u>of the garden:</u></em>

Area of the garden = $(side $ length)^2$

Area = $(x + 2)^2$

Plug in the value of x

Area = $(4 + 2)^2 = 6^2 = 36 $ ft^2$

<u><em>Find the </em></u><u><em>perimeter </em></u><u><em>if the garden size is doubled:</em></u>

Perimeter of the new garden = 2 x 24 = 48 ft

<em><u>Find the </u></em><em><u>area </u></em><em><u>if the garden size is doubled:</u></em>

Perimeter of the new garden = 2 x 36 = 72 sq. ft

In summary, if the perimeter of the garden is (14x - 32) ft and has a side length of (x + 2) ft:

the perimeter = 24 ft
the area = 36 sq. ft
if the perimeter of the garden is doubled, the perimeter of the new garden = 48 ft
if the area of the garden is doubled, the area of the new garden = 72 sq. ft

Learn more here:

brainly.com/question/13511952

4 0

2 years ago

(3x ^3 + 4x^2)+(3x3-4x^2-9x)=

strojnjashka [21]

Answer:=6x3−9c

Step-by-step explanation:

3x3+4x2+3x3−4x2−9c

=3x3+4x2+3x3+−4x2+−9c

Combine Like Terms:

=3x3+4x2+3x3+−4x2+−9c

=(3x3+3x3)+(4x2+−4x2)+(−9c)

=6x3+−9c

6 0

3 years ago

One apple costs $0.55 at the grocery store. Customers receive on free apple for every 8 apples that they buy. Anna paid a total

chubhunter [2.5K]

Answer:

Anna received 2 free apples

Step-by-step explanation:

no probm

6 0

3 years ago

Read 2 more answers

Find the surface area of the following cylinder. Round your answers to the nearest tenth.

Katarina [22]

Answer: 628

Step-by-step explanation:

2πr^2+2πrh

2(3.14)(5)^2+2(3.14)(5)(15)

2(3.14)(25)+2(3.14)(75)

2(78.5)+2(235.5)

157+471

628

5 0

3 years ago

Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

Or

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

This is a parabola (0,2.5) and turns upside down.

4 0

3 years ago