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2 years ago

Complete the square for the expression

Mathematics

1 answer:

melamori03 [73]2 years ago

4 0

Answer:

x^2 + 14x + 49 = 0

Step-by-step explanation:

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Please help!

blagie [28]

Given the two options above, in order to come up with the best plan we have to calculate the future value of money in each plan.
compound interest is given by: $FV=p(1+ \frac{r}{100})^n$

Option 1
p=$500
r=2%=0.02
t=1 year
$FV=500(1+0.02)^1=$510$

Option 2
p=$500
r=2/12=1/6
n=1*12=12
hence:
$FV=500(1+\frac{ \frac{1}{6}}{100})^{12}
$
=$509.09
Comparing the two plans above, option 1 is the best.

b] Option 1 is the best because she will secure $510 as compared to option 2 which has interest rate that reduces her amount by $1 after one year due to annual charges. The total amount of money she will have at the end of the plan is $510.

8 0

3 years ago

Tia, Leah, and Tim all solve the problem 3(-x + 4) = -3x - 12. Tia solved and decided that the solution is x= 4. Leah solved the

nexus9112 [7]

Answer:

Tina

Step-by-step explanation:

bc if you sub in 4 for x the equations on both sides are 0

check:

-4 + 4 = 0 -3 x 4 = -12

0 x 3 = 0 12 + -12 = 0

0 = 0

please mark this as brainiest!!!!

5 0

3 years ago

One of the children bought their teacher a mathematical plant for the classroom windowsill. At the end of the first day it had i

Vlad [161]

Answer:

18 days

Step-by-step explanation:

Here's a short table of heights:

day 0: height = 1

day 1: height = 1 + (1/2)(1) = 3/2

day 2: height = (3/2) + (1/3)(3/2) = 3/2 + 1/2 = 2

The pattern of heights is ...

(day, height) = (0, 1), (1, 1.5), (2, 2)

The plant is growing 1/2 its original height each day, so we can write the equation ...

h = 1 + d/2

We want to find the number of days (d) that result in a height of 10 (ten times the original height).

10 = 1 + d/2

9 = d/2 . . . . subtract 1

18 = d . . . . . multiply by 2

It took 18 days for the plant to grow to 10 times its original height.

5 0

3 years ago

64% of 75 tiles show work

Anarel [89]

48. Multiply 75 by 0.64

4 0

3 years ago

Read 2 more answers

If the Math Olympiad Club consists of 11 students, how many different teams of 3 students can be formed for competitions?

vivado [14]

Answer:

165 different teams of 3 students can be formed for competitions

Step-by-step explanation:

Combinations of m elements taken from n in n (m≥n) are called all possible groupings that can be made with the m elements so that:

Not all items fit
No matter the order
Elements are not repeated

That is, a combination is an arrangement of elements where the place or position they occupy within the arrangement does not matter. In a combination it is interesting to form groups and their content.

To calculate the number of combinations, the following expression is applied:

$C=\frac{m!}{n!*(m-n)!}$

It indicates the combinations of m objects taken from among n objects, where the term "n!" is called "factorial of n" and is the multiplication of all the numbers that go from "n" to 1.

In this case:

n: 3
m: 11

Replacing:

$C=\frac{11!}{3!*(11-3)!}$

Solving:

$C=\frac{11!}{3!*8!}$

being:

3!=3*2*1=6
8!=8*7*6*5*4*3*2*1=40,320
11!=39,916,800

So:

$C=\frac{39,916,800}{6*40,320}$

C= 165

<u><em>165 different teams of 3 students can be formed for competitions</em></u>

3 0

3 years ago