Gabriel and Jorge have a right triangle
Makayla has a equilateral
Emma has an obtuse
If you translate it to English I’ll answer for you
You just have to rearrange the formula.
So:
765 = 135 x m + 225
765 - 225 = 135 x m
540 = 135 x m
m = 540 / 135
m = 4
So four months.
Answer:
The area of the base is about 32 square meters
Step-by-step explanation:
V = pi times r^2 times h which is the formula.
Since the volume is 288, and the height is 9 it is,
288 = pi times r^2 times 9,
288/9 = pi times r^2 times 9/9
32/pi = pi/pi times r^2
10.2 = r^2
The square root of 10.2 is about 3.19
Area formula is pi times radius, r^2
3.19 times 3.19 or 3.19^2 = 10.1761
10.1761 times pi is 31.96 which is about 32 square meters.
I hope this helps!
By letting
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we get derivatives

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a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

Examine the lowest degree term
, which gives rise to the indicial equation,

with roots at r = 0 and r = 4/5.
b) The recurrence for the coefficients
is
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so that with r = 4/5, the coefficients are governed by

c) Starting with
, we find


so that the first three terms of the solution are
