Question

How many moles of P4 will form when 1 mole of Ca3(PO4)2 reacts with 3 moles of SiO2 and 2 moles of C? Ca3(PO4)2 + 6 SiO 2 + 10 C → P 4 + 6 Ca SiO 3 + 10 CO?

Answer 1

Answer:

0.5

Explanation:

We are given the moles of two reactants, so this could be a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

              2Ca₃(PO₄)₂ + 6SiO₂ + 10C → P₄ + 6CaSiO₃ + 10CO

n/mol:             1                 3

Calculate the moles of P₄ that can be formed from each reactant :

1. From Ca₃(PO₄)₂

$\text{Moles of P}_{4} = \text{1 mol Ca _{3} (PO}_{4})_{2} \times \dfrac{\text{1 mol P}_{4}}{\text{2 mol Ca _{3} (PO}_{4})}_{2} = \text{0.5 mol P}_{4}$

2. From SiO₂

$\text{Moles of P}_{4} = \text{3 mol SiO}_{2} \times \dfrac{\text{1 mol P}_{4}}{\text{6 mol SiO}_{2}} = \text{0.5 mol P}_{4}$

Each reactant forms 0.5 mol of P₄.