Explanation:
Since, NaCl exists as
and
in solution. Therefore, Van't Hoff factor (i) will be equal to 2.
Now, we assume that there are "n" moles of NaCl in the given solution. And, we assume that there is 1 kg of solvent (water).
So, ![\frac{\Delta P}{P} = i \times \frac{\text{no. of moles of NaCl}}{\text{Mass of water in kg}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20P%7D%7BP%7D%20%3D%20i%20%5Ctimes%20%5Cfrac%7B%5Ctext%7Bno.%20of%20moles%20of%20NaCl%7D%7D%7B%5Ctext%7BMass%20of%20water%20in%20kg%7D%7D)
![\frac{23.8 torr - 17.5 torr}{23.8 torr} = 2 \times \frac{n}{1}](https://tex.z-dn.net/?f=%5Cfrac%7B23.8%20torr%20-%2017.5%20torr%7D%7B23.8%20torr%7D%20%3D%202%20%5Ctimes%20%5Cfrac%7Bn%7D%7B1%7D)
0.264 = ![2 \times \frac{n}{1}](https://tex.z-dn.net/?f=2%20%5Ctimes%20%5Cfrac%7Bn%7D%7B1%7D)
n = 0.132
Also, moles of water will be calculated as follows.
Moles of water =
= 55.56 mol
Hence, mole fraction of NaCl is calculated as follows.
Mole fraction = ![\frac{0.132}{55.56 + 0.132}](https://tex.z-dn.net/?f=%5Cfrac%7B0.132%7D%7B55.56%20%2B%200.132%7D)
= ![2.37 \times 10^{-3}](https://tex.z-dn.net/?f=2.37%20%5Ctimes%2010%5E%7B-3%7D)
Hence, mole fraction of NaCl will be
.
At
, the vapor pressure will be calculated as follows.
71.9 - p = 18.98
p = 52.92 torr
Therefore, vapor pressure of the given solution is 52.92 torr.
On the ion name put the the numbers that match it
Excess alcohol is removed by Vacuum filtration.
<h3>What is vacuum filtration?</h3>
- Vacuum filtration is a methodology where a tension differential is kept up with across the channel medium by clearing the air beneath the channel paper.
- Vacuum filtration gives a power on the arrangement notwithstanding that of gravity and builds the pace of filtration.
- Vacuum filtration is the standard strategy utilized for isolating a strong fluid blend when the objective is to hold the strong (for instance in crystallization).
<h3>How do you dry a product after vacuum filtration?</h3>
- The strong can be dried rapidly by washing the strong with an unpredictable fluid (methanol, CH3)2CO, or ether are normal) that the strong won't break up in. In the event that the filtrate is to be gathered, change the getting jar prior to washing.
To learn more about vacuum filtration from the given link
brainly.com/question/24082009
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Answer:
The mass percent of alcohol in a solution is 19.8 %
Explanation:
First of all we calculate the mass of each compound from the solution.
Solute → Ethyl alcohol
Solvent → Water
To determine the mass, we use density
Density = mass / volume → Mass = Density . volume
Mass of solute: 0.8 g/mL . 62 mL = 49.6 g
Mass of solvent: 1 g/mL . 200 mL = 200 g
Mass of solution = Solvent's mass + Solute 's mass
200 g + 49.6 g = 249.6 g
Mass percent of alcohol → (mass of alcohol / Total mass) . 100
(49.6 g / 249.6 g) . 100 = 19.8 %