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Butoxors [25]
4 years ago
12

What is the slope of the line represented by the equation 10×+5y=4a.2b.1/2c.-1/2d.-2

Mathematics
1 answer:
VikaD [51]4 years ago
6 0
Equation: 10x + 5y = 4
5y = -10x + 4

Divide the equation by 5, 
y = -2x + 4/5

Now Compare it with, y = mx + c
Here,m = -2

In short, Your Answer would be Option D

Hope this helps!
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I did the first one but can you help me with the second one plz??
yanalaym [24]

the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.

\bf \cfrac{5}{2}s=\cfrac{3}{2}s+s\implies \cfrac{5}{2}s=\cfrac{3}{2}s+\cfrac{s}{1}\implies \cfrac{5}{2}s=\stackrel{\textit{using the LCD of 2}}{\cfrac{(1)3s+(2)s}{2}} \\\\\\ \cfrac{5}{2}s=\cfrac{3s+2s}{2}\implies \cfrac{5}{2}s = \cfrac{5}{2}s

5 0
3 years ago
What quadrant does this lie in: cot(theta)>0 and sin(theta)>0?
Mice21 [21]

Answer:

lies on IV quadrant

Step-by-step explanation:

6 0
3 years ago
Can so,e one help?! PLSSSSSS
andrew-mc [135]

Answer:

10 1/2

Step-by-step explanation:

8 0
2 years ago
Does the sum 1-5+1-5 =makes sense in this situation explain
Ne4ueva [31]
Yes 1 -5 then  tou add 1 +5


4 0
3 years ago
Read 2 more answers
Please show work on these questions!!!
asambeis [7]

Answer:

- 14π/9; 108°; -√2/2; √2/2

Step-by-step explanation:

To convert from degrees to radians, use the unit multiplier \frac{\pi }{180}

In equation form that will look like this:

- 280° × \frac{\pi }{180}

Cross canceling out the degrees gives you only radians left, and simplifying the fraction to its simplest form we have -\frac{14\pi }{9}

The second question uses the same unit multiplier, but this time the degrees are in the numerator since we want to cancel out the radians.  That equation looks like this:

\frac{3\pi }{5} × \frac{180}{\pi }

Simplifying all of that and canceling out the radians gives you 108°.

The third one requires the reference angle of \frac{3\pi }{4}.

If you use the same method as above, we find that that angle in degrees is 135°.  That angle is in QII and has a reference angle of 45 degrees.  The Pythagorean triple for a 45-45-90 is (1, 1, √2).  But the first "1" there is negative because x is negative in QII.  So the cosine of this angle, side adjacent over hypotenuse, is -\frac{1}{\sqrt{2} }

which rationalizes to -\frac{\sqrt{2} }{2}

The sin of that angle is the side opposite the reference angle, 1, over the hypotenuse of the square root of 2 is, rationalized, \frac{\sqrt{2} }{2}

And you're done!!!

7 0
4 years ago
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