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Korolek [52]
3 years ago
7

What is the answer to -7(n+2)=-14-7n

Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0
The answer is 1.
Im too lazy to show the work, but heres how I checked

-7(1 + 2) = -14 - 7
-7 + (-14) = -14 - 7
-21 = -21
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Alina, Robert, and Makayla are on the student council at their high school.
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Step-by-step explanation:

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List the perfect cubes between 1000 and 3000 that are even numbers
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 12^3 = 1728; 14^3 = 2744;
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Z wants to buy five shirts worth 34 dollars each and three baseball caps worth 31
ella [17]

Answer:

$199.50

Step-by-step explanation:

10% discount of $34 = 10/100*34 = $3.40

so, a single shirt costs $34-$3.40 = $30.60

half off = 50% discount of $31 = 50/100*31 = $15.50

so, a single cap costs $31-$15.50 = $15.50

so, 5 shirts and 3 caps cost now

5*$30.60 + 3*$15.50 = $153 + $46.50 = $199.50

but careful - can this be a trick question ?

the phrasing of the problem description can also suggest that the discounts are only listed to confuse us and are already included in the mentioned prices ("worth" $34 - what does that mean ? because including the discounts they are currently "worth" their prices).

then it would just plainly be

5*$34 + 3*$31 = $170 + $93 = $263

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3 years ago
Abigail was skateboarding home when the wheel axle of her skateboard broke. She had already traveled two thirds of the way home
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Answer:

I think that her taking the skateboard is 4 times as fast as her walking.

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4 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
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