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emmasim [6.3K]
3 years ago
9

2. Simplify: (-4a+b-2c) - (3a +26-c) -)

Mathematics
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

I thinks its, -7a+b-3c+26

Step-by-step explanation:

idk

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Prove that root 7 is irrational by the method of contradiction
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Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

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Step-by-step explanation:

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Read 2 more answers
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