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Annette [7]
3 years ago
10

a water faucet leaked 2 1/6 liters of water every 1/3. hour it leaked at a rate of how many liter per hour?

Mathematics
2 answers:
SIZIF [17.4K]3 years ago
7 0

Answer:  The required rate at which the water faucet leaked is 6.5 liters per hour.

Step-by-step explanation:  Given that a water faucet leaked 2\frac{1}{6} liters of water every \frac{1}{3} hour.

We are to find the rate in liter per hour at which the water faucet leaked.

We will be using the UNITARY method to solve the problem.

We have

Number of liters of water faucet leaked in \frac{1}{3} hour. is

2\dfrac{1}{6}=\dfrac{13}{6}~\textup{liters}.

Therefore, the number of liters of water faucet leaked in 1 hour is

\dfrac{\frac{13}{6}}{\frac{1}{3}}=\dfrac{13}{6}\times3=\dfrac{13}{2}=6.5~\textup{liters}.

Thus, the required rate at which the water faucet leaked is 6.5 liters per hour.

ladessa [460]3 years ago
4 0
2 1/18. Hope this will help you
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Can you please help me with this problem? It shouldn't be to hard if you've done Algebra one.
seropon [69]
A) Y=0.12x and the Y value is dependent whole X value is independent
b) Just make a table and multiple each value by the equation
c) The domain would be the lowest and highest values of X and the range would be the lowest and highest values of Y (double check me on this to be sure)
d) A day = (0.12)(300)+(0.12)(750)+(0.12)(1050)
A week = (0.12)(300)+(0.12)(750)+(0.12)(1050) and multiply that by 7
5 0
3 years ago
What's larger 0.75 or 1/2
Brilliant_brown [7]
Okay let's see.. 0.750
1.200
As we see 1 is bigger than 0.So that means 1/2 is bigger.Hope this helps! (;
8 0
3 years ago
Read 2 more answers
9. Dagne measures and finds that she
Naddik [55]

Answer; 47.27 Inches

Let the height of Dagne be x.

Now we are told that she can do a vertical jump that is 27.5%  of her height. This is represented as 0.275x.

Now we are told the height she can jump is 13.2. Thus;

0.275x = 13.2

x = 13.2/0.275

x = 47.27 inches

7 0
2 years ago
1. A MAP SCALE READS 1CM:5KM. IF A DISTANCE ON THE MAP MEASURES 7CM, THE ACTUAL DISTANCE WILL BE?. 2. A SCHOOL DINING HALL IS 35
Agata [3.3K]

Answer:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

Step-by-step explanation:

Solution 1.

Reading of map scale = 1cm:5km

i.e. 1 cm is equivalent to 5 km

Measurement of map  = 7 cm

Actual distance = Measurement of map \times 5

Actual distance = 7 \times 5 = <em>35 km</em>

-------------------

Solution 2.

Length of dining hall = 35 m

Measurement of map = 7 cm

Scale = Measurement of map : Length of dining hall (i.e. ratio)

Scale = 7 cm :35 m = <em>1 cm : 5 m</em>

-------------------

Solution 3.

Length of building = 30 m

Scale = 1 cm to 5m

5 m is equivalent to 1 cm on scale

1 m is equivalent to \frac{1}{5} cm on scale

30m is equivalent to \frac{1}{5} \times 30 = <em>6 cm</em> on scale

-------------------

Solution 4.

Angle of elevation of A from B = 42^\circ

Angle of depression of B from A = ?

Please refer to the image attached, we can clearly observe that both the angles (i.e. angle of elevation from A to B and angle of depression from B to A )will be equal.

Angle of depression of B from A = 42^\circ

-------------------

Solution 5.

Given that:

String length, or hypotenuse of triangle BC= 25 m

Angle of string with horizontal, \angle B  = 42^\circ

Please refer to the attached image for the clear understanding of the situation.

To find:

Height, AC = ?

We can use trigonometric identity:

sin\theta = \dfrac{Perpendicular}{Hypotenuse}

OR

sinB = \dfrac{AC}{BC}\\\Rightarrow sin42^\circ = \dfrac{AC}{25}\\\Rightarrow AC = 25 \times 0.67\\\Rightarrow AC = 16.73 m

============

So, the answers are:

1. 35 km

2. 1 cm to 5m

3. 6 cm

4. 42^\circ

5. 16.73 m

7 0
3 years ago
If m&lt;9=97 and m&lt;12=114, find each measure.
seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0
3 years ago
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