-2 -8 is the answer for this question x=-2 and x=-8
Figure is missing, so i have attached it.
Answer:
it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Step-by-step explanation:
The standard form of equation of an ellipse is;
x²/a² + y²/b² = 1
From the figure in the image attached, we can see that the radius is; a = 52/2 = 26 ft
While the value of b = 13 ft
Thus;
x²/26² + y²/13² = 1
x²/676 + y²/169 = 1
We want to find the height of the archway of the bridge 5 feet from the center.
Thus, we will plug in 5 for x to get;
5²/676 + y²/169 = 1
(25/676) + (y²/169) = 1
Multiply through by 676 to get;
25 + 4y² = 676
4y² = 676 - 25
y² = 651/4
y² = 162.75
y = 12.76 ft
Thus height of the truck is 12 ft and so it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Answer:
15. Area of parallelogram = bh
b = 9m
h = 4m
a = 9*4 = 36m^2
You can also use the rectangle property here.
a = l*b
l = 9
b = 6
a = 9*6 = 54 m^2
Though I would prefer the first one better.
16. Area of triangle = 1/2*bh
b = 17m
h = 3
a = 17*3/2 = 51/2 = 25.5m^2
18. Area of a trapezium = a+b/2*h (a and b are two parallel sides and h the height)
a = 15
b = 7
h = 15
a = 15+7/2*15 = 22/2*15 = 11*15 = 165m^2
19. Area of triangle = 1/2*bh
b = 24
h = 7
a = 24*7/2 = 168/2 = 84
Hope u understood
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Pythagorean Theorem: a^2 + b^2 = c^2
a = 6
c = 9
b = ?
6^2 + b^2 = 9^2
36 + b^2 = 81
b^2 = 81 - 36
b^2 = 45
b = sqrt(45)
b = 6.71 miles