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nalin [4]
3 years ago
5

Isaac sold 58 of his baseball cards at a collectors show. If this represented 14.5% of his total collection, how many baseball c

ards did Isaac have before he sold his cards?
Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

400\ cards

Step-by-step explanation:

Let

x------> amount of baseball cards Isaac had before he sold

we know that

14.5\%=14.5/100=0.145

so

0.145x=58

Solve for x

x=58/0.145

x=400\ cards

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Answer:

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}  

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And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

We don't have a prior estimation for the proportion \hat p so we can use 0.5 as an approximation for this case  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

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3 years ago
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</span>\frac{1}{2} \times n = \frac{1}{2}n
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</span>- (2n + 3) = -2n -3
<span>
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</span>\frac{1}{2}n - 2 - 3 = 3 - 2n - 3
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