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ehidna [41]
3 years ago
15

The roof of a tower in a castle is shaped like a cone. The height of the roof is 30 ft, and the radius of the base is 15 ft. Wha

t is the area of the roof?
Mathematics
1 answer:
Serhud [2]3 years ago
4 0

 

d.

1,580.6 ft2 is the answer


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Which of the following expressions is equivalent to 15x+y−x−10y?
lions [1.4K]
14x-9y is the answer
6 0
2 years ago
Weegee needs help pleaseeeeee help for brainliest
FinnZ [79.3K]

Answer:

b) It has a value less than 2

Step-by-step explanation:

Divide both sides of the inequality by 12 to get

t < 2 so the answer is b)

4 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
A and B are two events.
maria [59]

Answer:

0.8

Step-by-step explanation:

We can solve P(A or B) by using the following:

P(AorB)=P(A)+P(B)-P(AandB)

Since we know P(A) = 0.6, P(B) = 0.3 and P(A and B) = 0.1 we obtain:

P(AorB)=0.6+0.3-0.1=0.8


4 0
3 years ago
Given : circle x with radius r and circle y with radius s
tigry1 [53]

Answer:

we need to know the variables

Step-by-step explanation:


5 0
3 years ago
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