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3 years ago

What is greatest to least 1.001,1.1,1.403,1.078

Mathematics

2 answers:

RSB [31]3 years ago

7 0

1.403, 1.1, 1.078, 1.001

Vlad [161]3 years ago

4 0

From greatest to least, 1.403, 1.1, 1.078, 1.001 This can be seen easier by putting zeros at the end of some numbers, but you don't have to. Example: 1.403, 1.100, 1.078, 1.001

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I need help pls thank you and I'll send better pics

kakasveta [241]

$\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}$

Explanation:

$\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}$ $\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}$ $\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}$

$\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}$ $\text{output = input + 5}$

5 0

1 year ago

Which fraction is not equivalent to 7 /30

dybincka [34]

These are the ones that are not equivalent to eachother. 1. 18/30
2. 8/10
3. 4/9
4. 14/18
5. 10/20
6. 20/32
7. 18/30

8 0

4 years ago

Read 2 more answers

When a deposit of $1000 is made into an account paying 2% interest, compounded annually, the balance, $B, in the account after t

labwork [276]

Answer:

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

Step-by-step explanation:

Given a function y, the average rate of change S of y=f(x) in an interval $(x_{s}, x_{f})$ will be given by the following equation:

$S = \frac{f(x_{f}) - f(x_{s})}{x_{f} - x_{s}}$

In this problem, we have that:

$B(t) = 1000(1.02)^{t}$

Find the average rate of change in the balance over the interval t = 0 to t = 5.

$B(0) = 1000(1.02)^{0} = 1000$

$B(5) = 1000(1.02)^{5} = 1104.08$

Then

$S = \frac{1104.08 - 1000}{5-0} = 20.82$

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

8 0

3 years ago

If f(x)=2x+5, then f(4) represents what

RSB [31]

<span>f(x)=2x+5
then
</span><span>f(4)=2(4) +5 = 8 + 5 = 13

hope it helps</span>

6 0

3 years ago

A van can travel 18 miles on each gallon of gasoline. at that rate how many miles can the van travel on 15 gallons of gasoline

tensa zangetsu [6.8K]

18 / 1 = x / 15......18 miles to 1 gallon = x miles to 15 gallon
cross multiply
(1)(x) = (18)(15)
x = 270 miles

7 0

3 years ago

Read 2 more answers