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Flura [38]
3 years ago
9

Ava was making muffins. She used 1 1/3 tsp of cinnamon and 1/2 tsp of nutmeg. How many teaspoons of spice did Ava use?  

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
Actually your answer is wrong. Ava has already use 1 teaspoon of spice plus 1/3 teaspoon plus another 1/2 teaspoon of spice. 1/3 + 1/2 = 5/6 so the answer is 1 5/6 teaspoons of spice.
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Please help explain how to solve problem 16?
Anarel [89]
Here is the problem.....√(15x + 10) = 2x+3

to remove the square root, we do the opposite which is to square everything.

(√(15x + 10))² = (2x + 3)²      (the square negates the square root)
15x + 10 = (2x +3)(2x + 3)    (use the distributive property to continue)
15x + 10 = 4x² + 6x + 6x + 9  (combine like terms)
15x + 10 = 4x² + 12x + 9      (subtract 15x and 10 from each side)
-15x - 10          -15x - 10
0 = 4x² - 3x - 1                      (factor completely)
(x - 1) (4x + 1)                    (set each to equal 0)

x - 1 = 0                4x + 1 = 0
x = 1                      4x = -1
                               x = -1/4

place both into the equation to check for reasonableness...we see the negative number is not reasonable, but the x value of 1 is a solution.

answer is 1
4 0
3 years ago
What is 11+23/60 as a mixed number
hodyreva [135]

Answer:

the answer is 683/60

Step-by-step explanation:

just multiply 60 by 11 then add 23, or multiply the bottom number by the whole number then add the top number

3 0
3 years ago
NEED HELP ASAP!!
Solnce55 [7]

Answer:

Only Cory is correct

Step-by-step explanation:

The gravitational pull of the Earth on a person or object is given by Newton's law of gravitation as follows;

F =G\times \dfrac{M \cdot m}{r^{2}}

Where;

G = The universal gravitational constant

M = The mass of one object

m = The mass of the other object

r = The distance between the centers of the two objects

For the gravitational pull of the Earth on a person, when the person is standing on the Earth's surface, r = R = The radius of the Earth ≈ 6,371 km

Therefore, for an astronaut in the international Space Station, r = 6,800 km

The ratio of the gravitational pull on the surface of the Earth, F₁, and the gravitational pull on an astronaut at the international space station, F₂, is therefore given as follows;

\dfrac{F_1}{F_2} = \dfrac{ \dfrac{M \cdot m}{R^{2}}}{\dfrac{M \cdot m}{r^{2}}} = \dfrac{r^2}{R^2}  = \dfrac{(6,800 \ km)^2}{(6,371 \ km)^2} \approx  1.14

∴ F₁ ≈ 1.14 × F₂

F₂ ≈ 0.8778 × F₁

Therefore, the gravitational pull on the astronaut by virtue of the distance from the center of the Earth, F₂ is approximately 88% of the gravitational pull on a person of similar mass on Earth

However, the International Space Station is moving in its orbit around the Earth at an orbiting speed enough to prevent the Space Station from falling to the Earth such that the Space Station falls around the Earth because of the curved shape of the gravitational attraction, such that the astronaut are constantly falling (similar to falling from height) and appear not to experience gravity

Therefore, Cory is correct, the astronauts in the International Space Station, 6,800 km from the Earth's center, are not too far to experience gravity.

6 0
3 years ago
I just need help with number 2, thank you
alekssr [168]

It represents the thing the avadocate needs to be muiltiplied by

4 0
3 years ago
Is (a + b) and (a - b)? perfect square trinomials?<br> O True<br> O False
lisabon 2012 [21]

Answer:

False

Step-by-step explanation:

Pos and negs cannot be perfect square trinomials

8 0
3 years ago
Read 2 more answers
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