The following data summarizes results from 952 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedistrian was intoxicated or the diriver was intoxicatedo Pedestrian intoxicated
yes (81) (51)
no (225) (552)
2 answers:
Answer:
0.139
Step-by-step explanation:
Number of pedestrians that were intoxicated 81
Number of pedestrians that were not intoxicated 225
Number of drivers that were intoxicated 51
Number of drivers that were not intoxicated 552
Total number of deaths 952
Probability of pedestrians intoxicated or driver intoxicated is
81/952 + 51/952 = 132/952 = 0.139
Answer:
0.3927
Step-by-step explanation:
Given
Pedestrian intoxicated
Yes (81) (51) ---- (132)
No (225) (552) --- (777)
Total: (306) (603) --- (909)
Let P(P) = the probability that the pedistrian was intoxicated
Let P(D) = T probability that the diriver was intoxicated
To calculate P(D or P)?
P(D or P) is given as P(D) + P(P) - P(P and D)
P(P) = 306/909
P(D) = 132/909
P(P and D) = 81/909
P(P or D) = 306/909 + 132/909 - 81/909
P(P or D) = 357/909
P(P or D) = 0.3927
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