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monitta
2 years ago
15

The base of a ladder is placed 2.8m away from a tree that is 4.5m tall. The end of the ladder touches the top of the tree. Calcu

late the length of the ladder.
Mathematics
2 answers:
kicyunya [14]2 years ago
7 0
Answer: The length is 7.3m
ahrayia [7]2 years ago
4 0

Answer:

The length is 7.3m

Step-by-step explanation:

The end of the ladder touches the top of the tree when kept at 2.8m away from the tree.

The Tree is 4.5m tall

The length of the ladder will be: 2.8+4.5 = 7.3

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You have a cake that is 10 inches in diameter. You expect 12 people to share it, so you cut it into 12 equal slices. Before you
Karo-lina-s [1.5K]

Answer:

3.5355 inches

Step-by-step explanation:

Area should be same the concentric circle and rest piece .

let's consider the radius of concentric circle as r

so it's area is π r²

area of whole circle is π (5)" ( because diameter is 10 inches)

so the area of rest piece is π (5)² - π r²

π (5)² - π r² = π r²

5² = 2r²

r² = 25/2

r = √(25/2)

r = 3.5355 inches

4 0
3 years ago
A person places $4080 in an investment account earning an annual rate of 5.7%, compounded continuously. Using the formula
tangare [24]

We have been given that a person places $6340 in an investment account earning an annual rate of 8.4%, compounded continuously. We are asked to find amount of money in the account after 2 years.

We will use continuous compounding formula to solve our given problem as:

, where

A = Final amount after t years,

P = Principal initially invested,

e = base of a natural logarithm,

r = Rate of interest in decimal form.  

Upon substituting our given values in above formula, we will get:

Upon rounding to nearest cent, we will get:

Therefore, an amount of $7499.82 will be in account after 2 years.

4 0
3 years ago
Read 2 more answers
Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv
Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

   = (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = \dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}

Let dD/dT = 0 to find the critical value we will get

\dfrac{70000000\left(291T^2-24298T+91800\right)}  = 0

Using formula of quadratic, we get the roots:

T =  79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8)    a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0
4 years ago
Which function can be used to find the number of cells of bacteria in the population at time t
Nonamiya [84]

Answer:

db / dt = kb  

this becomes b(t) = Ce^(kt)  

C = 100, the initial population  

P(1) = 420 = 100 e^(1k)  

4.2 = e^k  

ln 4.2 = k  

a) thus, b(t) = 100 e^(t ln 4.2)  

b) b(3) = 100 e^(3 ln 4.2)  

c) growth constant will still be ln 4.2 (constant percentage of populatioin)  

d) 10000 = 100 e^(t ln 4.2)  

100 = e^(t ln 4.2)  

ln 100 = t ln 4.2  

t = ln 100 / ln 4.2

Step-by-step explanation:

6 0
3 years ago
12) Write the equation of a rational function
aev [14]

Answer:

\frac{4(x - 5)(x + 7)(x - 12)}{(x + 1)(x)(x - 12)}

Step-by-step explanation:

A rational function is

\frac{p(x)}{q(x)}

where q(x) doesn't equal zero.

If p is a asymptote, or hole at that value, then we will use

(x - p)

Step 1: We have asymptote as 0 and -1 so our denomiator will include

(x - 0)(x - ( - 1)

Which is

(x)(x + 1)

So our denomator so far is

\frac{p(x)}{x(x + 1)}

Step 2: Find Holes.

Since 12 is the value of the hole,

(x - 12)

is a the binomial.

This will be both on the numerator and denomator so qe have

\frac{(x - 12)}{x(x + 1)(x - 12)}

Step 3: Put the x intercepts in the numerator.

Since 5 and -7 is the intercepts,

\frac{(x - 12)(x - 5)(x + 7)}{x(x + 1)(x - 12)}

Step 4: Horinzontal Asymptotes,

Multiply the numerator and denomiator out fully,

\frac{  {x}^{3} - 10 {x}^{2}  - 59x + 420 }{ {x}^{3} - 12 {x}^{2}   + x - 12}

Take a L

look at the coefficients,

Notice they have the same degree,3, this means if we divide the leading coefficents, we will get our horinzonral asymptote.

Multiply the numerator by 4.

\frac{4(x - 12)(x - 5)(x - 7)}{x(x + 1)(x - 12)}

Above is the function,

5 0
3 years ago
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