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3 years ago

How do I solve this?

Mathematics

2 answers:

djyliett [7]3 years ago

4 0

Answer:

5a-30

Step-by-step explanation:

multiply 5 since its outside by the numbers inside the parethesis

MAVERICK [17]3 years ago

4 0

I think it would be (5 × a) + (5 × -6)

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Caleb is putting tile down in his bathroom and needs to know the perimeter of the floor. Two sides rectangular floor are 5 1/3 f

ladessa [460]

Answer:

20 1/6 ft

Step-by-step explanation:

The perimeter is the sum of the lengths of the sides:

2×(5 1/3 ft) + 2×(4 3/4 ft) = 10 2/3 ft + 8 6/4 ft

= 10 2/3 ft + 9 2/4 ft . . . . change 6/4 ft to 1 1/2 ft

= 10 8/12 ft + 9 6/12 ft = 19 14/12 ft . . . . . use common denominator of 1/12 ft

= 20 2/12 ft . . . . . . change 14/12 ft to 1 2/12 ft; next reduce that fraction

= 20 1/6 ft . . . . perimeter of Caleb's bathroom

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3 years ago

Chase goes out to lunch. The bill, before tax and tip, was $14.30. A sales tax of 6% was added on. Chase tipped 23% on the amoun

g100num [7]

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3 years ago

1815 + 0230 = subtract as n military time

Anika [276]

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Answer: 20:45

I hope this helped!

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5 0

3 years ago

Read 2 more answers

uranmaximum [27]

Answer:

ok....let me try .....

ohhhh leave it. gu

<h2>..ok bro....sorry don't be angry bjhujj</h2>

6 0

3 years ago

Recall the equation for a circle with center (h, k) and radius r. At what point in the first quadrant does the line with equatio

lina2011 [118]

Answer:

The point of intersection is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

Step-by-step explanation:

We want to find the point in QI at which the line with the equation:

$y=0.5x+5$

Intersect a circle with a radius of 3 and a center of (0, 5).

First, write the equation of a circle. The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

Since our center is (0, 5), h = 0 and k = 5. The radius is 3. So, r = 3. Substitute:

$(x-0)^2+(y-5)^2=(3)^2$

Simplify:

$x^2+(y-5)^2=9$

At the point where the two equations intersect, its x-coordinate and y-coordinate will be the same. Therefore, we can substitute the equation of the line into the equation of the circle and solve for x. So:

$x^2+((0.5x+5)-5)^2=9$

Simplify:

$x^2+(0.5x)^2=9$

Square:

$x^2+0.25x^2=9$

Combine like terms:

$\displaystyle 1.25x^2=\frac{5}{4}x^2=9$

Solve for x:

$\displaystyle \begin{aligned} x^2&=\frac{36}{5} \\ x&=\pm\sqrt{\frac{36}{5}} \\ x&\Rightarrow \frac{6}{\sqrt{5}}=\frac{6\sqrt{5}}{5}\approx2.68\end{aligned}$

Note that since we are looking for the point of intersection in QI, x should be positive. So, we can ignore the negative answer.

To find the y-coordinate, substitute the x-value back into either equation. Using the linear equation:

$\displaystyle y=0.5\left(\frac{6\sqrt{5}}{5}\right)+5=\frac{3\sqrt{5}}{5}+5\approx 6.34$

So, the point of intersection in QI is:

$\displaystyle \left(\frac{6\sqrt{5}}{5}, \frac{3\sqrt{5}}{5}+5\right)\approx \left(2.68, 6.34)$

6 0

3 years ago