90 hazelnuts = 125g
Therefore, the mass of one hazelnut is this...
90 / 90 = 125 / 90
1 hazelnut = 25/18 grams
630 calories = 100 grams
100 divided by 25/18 = 72
Therefore...
630 / 72 = 1 hazelnut
AND THE ANSWER IS
8.75 calories = 1 hazelnut
Answer:
19+19= x
So x, is 38. Just add 19 and 19
Answer: Hence, the probability that he will get at least one lemon is 0.70.
Step-by-step explanation:
Since we have given that
Number of cars = 30
Number of lemon cars = 10
Number of other than lemon cars = 30-10 = 20
According to question, he bought 3 cars,
we need to find the probability that you will get at least one lemon.
So, P(X≤1)=1-P(X=0)=1-P(no lemon)
Here, P(no lemon ) is given by

so, it becomes,

Hence, the probability that he will get at least one lemon is 0.70.
Extraemos los datos del problema:
- Capital Inicial → C₀ = S/.25000
- Interés bimestral → i = 8 % = 0.08
- Periodos → n = 3
<h2 /><h2>Bimestre 1:</h2>
Capital Inicial Bimestre → C = S/.25000
Tasa de interés bimestral:
I = C×i
I = S/.25000 × 0.08
I = S/.2000
Monto final:
M = C + I
M = S/.25000 + S/.2000
M = S/.27000
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 27000 - 25000) / 25000
% = 8
<h2>Bimestre 2:</h2>
Capital Inicial Bimestre → C = S/.27000
Tasa de interés bimestral:
I = C×i
I = S/.27000 × 0.08
I = S/.2160
Monto final:
M = C + I
M = S/.27000 + S/.2160
M = S/.29160
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 29160 - 25000) / 25000
% = 16.64
<h2>Bimestre 3:</h2>
Capital Inicial Bimestre → C = S/.29160
Tasa de interés bimestral:
I = C×i
I = S/.29160 × 0.08
I = S/.2332.8
Monto final:
M = C + I
M = S/.29160 + S/.2332.8
M = S/ 31492.8
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 31492.8 - 25000) / 25000
% = 25.97
Answer:
A h+p ≤15
50h+500p ≥ 2500
Step-by-step explanation:
h = headphone and
p = pianos
We can only ship a maximum of 15 total
h+p ≤15
We must sell at least 2500 dollars of product. Headphones are 50 and pianos are 500
50h+500p ≥ 2500