What is the vertex of the equation y = (x - 3)2 + 7?

Mathematics

1 answer:

jeka57 [31]3 years ago

6 0

Answer:

(3,7)

Step-by-step explanation:

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A restaurant offers a combo special with 3 different sandwiches, 2 different salads, and 5 different drinks. From how many diffe

m_a_m_a [10]

Answer:

30 ways

Step-by-step explanation:

Given the following information:

3 different sandwiches
2 different salads
5 different drinks

Let assume that the combo contains: 1 sandwich, 1 salad, and 1 drink

Hence, we have:

The total possible ways of choosing sandwiches she can choose is: 3

The total possible ways of choosing salads she can choose is: 2

The total possible ways of choosing drinks she can choose is: 5

=> Total ways = 3*5*2 = 30 ways or there are 30 different combos Keisha can choose

Hope it will find you well.

5 0

3 years ago

1.5 Determine the degree of the following algebraic expressions:

tatuchka [14]

By identifying the largest exponent in each expression, we see that the answers are:

a) D = 3.

b) D = 5.

c) D = 0.

<h3></h3><h3>How to determine the degree of an expression?</h3>

The degree is just the largest exponent of the variable in an expression.

First, we have:

a) √3xyz - 5

The largest exponent is on the term √3*xyz is 3 (because we add the 3 exponents 1 of x, y, and z) so this expression has a degree of 3.

b) y² - 3y⁵ -y + 2y³ - 4

Here the largest exponent is on the second term, so we can see that the degree is 5.

c) -10³

Here we don't have a variable, so this is a constant, which means that the degree is zero, because we could write:

-10³*x⁰

Where we use the fact that x⁰ = 1

If you want to learn more about degrees:

brainly.com/question/1600696

#SPJ1

6 0

2 years ago

Factorise x^2/4-y^2/4

Nuetrik [128]

Answer:

$\large\boxed{\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}}$

Step-by-step explanation:

$\dfrac{x^2}{4}-\dfrac{y^2}{4}=\dfrac{x^2}{2^2}-\dfrac{y^2}{2^2}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\=\left(\dfrac{x}{2}\right)^2-\left(\dfrac{y}{2}\right)^2\qquad\text{use}\ (a-b)(a+b)=a^2-b^2\\\\=\left(\dfrac{x}{2}-\dfrac{y}{2}\right)\left(\dfrac{x}{2}+\dfrac{y}{2}\right)=\dfrac{x-y}{2}\cdot\dfrac{x+y}{2}$