Question:
Katy makes 48 cookies an hour. If she has 24 already, how long would it take her to make 120?
Answer:
It takes 2.5 hours for Katy to make 120 cookies
Step-by-step explanation:
Given:
Time taken to make 48 cookies = 1 hour
To Find:
Time taken to make 120 cookies = ?
Solution:
Time taken to make 48 cookies = i hour
So now time taken to make 1 cookie = 
So time taken to make 120 cookies
= Number of cookies X time taken to make one cookie
=>
=>
=> 2.5 hours
7(6+2) = 7(8)=56
The answer is:
7(6)=42 + 14=56
56 is the answer cause you use 7*8=56 so i hope that helps
Answer:
<em>Step-by-step explanation</em>
<em>thinked number = x</em>
<em>add 3 = +3 </em>
<em>multiply</em><em> </em><em>the</em><em> </em><em>result</em><em> </em><em>by</em><em> </em><em>7</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>
<em>brainliest</em><em> </em><em>appreciated</em>
<em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>
<span>#include <iostream>
using namespace std;
class InventoryTag {
public:
InventoryTag();
int getQuantityRemaining() const;
void addInventory(int numItems);
private:
int quantityRemaining;
};
InventoryTag::InventoryTag() {
quantityRemaining = 0;
}
int InventoryTag::getQuantityRemaining() const {
return quantityRemaining;
}
void InventoryTag::addInventory(int numItems) {
if (numItems > 10) {
quantityRemaining = quantityRemaining + numItems;
}
}
int main() {
InventoryTag redSweater;
int sweaterShipment = 0;
int sweaterInventoryBefore = 0;
sweaterInventoryBefore = redSweater.getQuantityRemaining();
sweaterShipment = 25;
cout << "Beginning tests." << endl;
// FIXME add unit test for addInventory
/* Your solution goes here */
cout << "Tests complete." << endl;
return 0;
}</span>
