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11111nata11111 [884]
3 years ago
12

Simplify 27^(-2/3) x 25^(1/2) x 5^0 9 5 9/5 5/9

Mathematics
1 answer:
Alja [10]3 years ago
7 0

Answer:

\frac{5}{9}

Step-by-step explanation:

Using the rules of exponents/ radicals

a^{\frac{m}{n} } ⇔ \sqrt[n]{a^{m} } , a^{0} = 1

a^{-m} = \frac{1}{a^{m} }

Given

27^{-\frac{2}{3} } × 25^{\frac{1}{2} } × 5^{0}

= \frac{1}{27^{\frac{2}{3} } } × \sqrt{25} × 1

= \frac{1}{9} × 5 × 1

=\frac{5}{9}

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The <em>quadratic</em> equation 3 · x² + 7 · x - 2 = 0 has a <em>positive</em> discriminant. Thus, the expression has two <em>distinct real</em> roots (<em>real</em> and <em>irrational</em> roots).

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Herein we have a <em>quadratic</em> equation of the form a · x² + b · x + c = 0, whose discriminant is:

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3 years ago
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2 years ago
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