Answer:
{7,14}
Step-by-step explanation:
Domain is always the X= Values
Answer:
Positive thinking is all of mind also positive
Step-by-step explanation:
What are you solving for?
If you are solving for × then I hope this helps
Let's solve for x.
f(x)= 100−10+e−0.1x
Step 1: Add 0.1x to both sides.
xf+0.1x=−0.1x+e+90+0.1x
xf+0.1x = e+90
Step 2: Factor out variable x.
x(f+0.1) = e+90
Step 3: Divide both sides by f+0.1.
x(f+0.1)/ f+0.1 =e+90/ f+0.1
x=e+90/ f+0.1
Answer:
x= e+90/ f+0.1
The question is incomplete. The complete question is :
Let X be a random variable with probability mass function
P(X =1) =1/2, P(X=2)=1/3, P(X=5)=1/6
(a) Find a function g such that E[g(X)]=1/3 ln(2) + 1/6 ln(5). You answer should give at least the values g(k) for all possible values of k of X, but you can also specify g on a larger set if possible.
(b) Let t be some real number. Find a function g such that E[g(X)] =1/2 e^t + 2/3 e^(2t) + 5/6 e^(5t)
Solution :
Given :

a). We know :
![$E[g(x)] = \sum g(x)p(x)$](https://tex.z-dn.net/?f=%24E%5Bg%28x%29%5D%20%3D%20%5Csum%20g%28x%29p%28x%29%24)
So, 

Therefore comparing both the sides,


Also, 
b).
We known that ![$E[g(x)] = \sum g(x)p(x)$](https://tex.z-dn.net/?f=%24E%5Bg%28x%29%5D%20%3D%20%5Csum%20g%28x%29p%28x%29%24)
∴ 

Therefore on comparing, we get

∴ 