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hjlf
3 years ago
14

Consider the curve y=ln(3x-1).let p be the point on the curve where x=2.

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0
A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient

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olchik [2.2K]

Peter's account is 910-40x, and Marla's account is 470-2x. This is a system, so you must find the number that makes both equations end up with the same number. Basically trial and error. Here is what I did:

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<h3>Answer: Bottom right corner (ie southeast corner)</h3>

This 3D solid is a strange sideways bowl shape. Each cross section is a ring to show the empty space.

======================================================

Explanation:

Check out the diagram below. The graph was created with GeoGebra. We have y = x^2 in red and x = y^2 in blue.

The gray region is the region between the two curves. We spin this gray region around the horizontal green line y = 1 to generate the answer mentioned above.

Note how (1,1) is a fixed point that does not move as this is on the line y = 1. Every other point moves to sweep through 3D space to create the solid figure. One way you can think of it is to think of propeller blades. Or you can think of a revolving door (the door is "flat" so to speak, but it sweeps out a 3D solid cylinder).

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lesantik [10]

Answer: D. 26 units

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