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3 years ago

The perimeter of a rectangle is 142m. The length is 2m more than the width. Find the dimensions. What is the length?

1 answer:

5 0

You have a rectangle that has a width of w. the length us 2 more than the width, so the lengthis w+2. the perimeter is 142. so 142=w+w+(w+2)+(w+2). because the perimeter is all 4 sides added together 2 of those sides being the length and 2 beingtje width. combine like terms to get 142=4w+4. now you subtract 4 from each side and get 138=4w. divide both sides by 4. you get w=34.5. now, w is the width. the length is 2 more than w, which is 34.5+2, or 36.5

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Answer:

10 ÷ 16

Step-by-step explanation:

The computation is shown below

Given that

Paul required to buy 5 by 8 pound of peanuts

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2 years ago

If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?

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Answer: The ΔVZX and ΔWXZ are not congruent by SAS.

Explanation:

It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.

Draw a figure as shown below,

According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.

From the given figure it is easily noticed that in ΔVZX and ΔWXZ,

$VX=WZ=40cm$ (given)

$\angle ZVX=\angle XWZ=22^{\circ}$ (given)

$XZ=XZ$ (common side)

Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.

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Answer:

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Step-by-step explanation:

Step 1:

3/5m = - 15 Equation

Step 2:

m = - 15 ÷ 3/5 Divide

Step 3:

m = - 15/1 × 5/3 Multiply

Answer:

m = - 25

Hope This Helps :)

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