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Ksenya-84 [330]
3 years ago
12

An advertising executive wants to determine if a new billboard placed in a city caused sales of her product to increase. To do t

his, she selects random stores that sell the product on the billboard and compares the amount sold in one business cycle before the billboard was placed to the sales of one business cycle after. Suppose that data were collected for a random sample of 10 stores, where each difference is calculated by subtracting the number of units sold in thousands before the billboard was placed from the number of units sold in thousands after the billboard was placed. Assume that the numbers are normally distributed. The executive uses the alternative hypothesis Ha:μd>0. Using a test statistic of t≈6.537, which has 9 degrees of freedom, determine the range that contains the p-value.

Mathematics
1 answer:
zepelin [54]3 years ago
3 0

Complete Question

The complete question is shown on the first and  second uploaded image

Answer:

The correct option is the first and the last option

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  10

   The null hypothesis is  H_o :  \mu_d  =  0

   The alternative hypothesis is  H_a :  \mu_d  >  0

    The test statistics is  t \approx 6.537

   The level of significance is  \alpha  = 0.05

Generally the p-value is mathematically represented as

    p-value  =  P(t >  6.537 )

From z-table  P(t >  6.537 ) = 0

So  

   p-value  =  0

From the value obtained we see that p-value < \alpha hence we reject the null hypothesis that the true mean difference between the number of units sold after the billboard was placed and the number of units sold before the billboard was placed is equal to zero

Thus we conclude that

Based on the results of the hypothesis test, there is not enough evidence at the level of significance(0.05) to suggest that the true mean difference between the number of units sold after the billboard was placed and the number of units sold before the billboard was placed is greater than zero    

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tatiyna

If the face is a square, then (l*l)

If the face is a triangle, then (b*h)(1/2)

If the face is a rectangle, then (l*w)

If the face is a circle, then (r²)(3.14)

You can then add all these faces up to get the total surface area of the prism.

3 0
3 years ago
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earnstyle [38]

Answer:

A, B, C

Step-by-step explanation:

whole number: the set of counting numbers, 1, 2, 3, ..., and includes the number 0.

integer: all whole numbers, zero, and all the negatives of the whole numbers: ..., -3, -2, -1, 0, 1, 2, 3, ...

rational: any number that can be written as a fraction of integers

irrational number: a number that cannot be written as a fraction of integers

1.00 is the same as 1

It is:

A whole number

B integer

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6 0
3 years ago
Read 2 more answers
Al saves pennies. He agreed to give 3/7 of his pennies to Bev if she would give 3/7 of what she got from Al to Carl and if Carl
ser-zykov [4K]

Answer:

2744 pennies.

Step-by-step explanation:

Let x represent the number of pennies Al have initially.

We have been given that Al agreed to give 3/7 of his pennies to Bev, so number of pennies Bev will get would be \frac{3}{7}x.

We are also told that Bev gave 3/7 of what she got from Al to Carl, so number of pennies that Carl will get would be \frac{3}{7}x\cdot \frac{3}{7}=\frac{9}{49}x.

Further, Carl gave 3/7 of what he got from Bev to Dani, so number of pennies that Dani will get would be \frac{9}{49}x\cdot \frac{3}{7}=\frac{27}{343}x.

We are also told that Dani received 216 pennies. Now, we will equate 216 to \frac{27}{343}x and solve for x as shown below:

\frac{27x}{343}=216

\frac{27x}{343}*343=216*343

27x=74088

\frac{27x}{27}=\frac{74088}{27}

x=2744

Therefore, Al have 2744 pennies initially.

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3 years ago
Write the set of points from −2 to 6 but excluding 3 and 6 as a union of intervals:
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Answer:

[-2,6] - {3} - {6}  =   [-2,3)  ∪   (3,6)

Step-by-step explanation:

Union Of Intervals

Let us assume two interval A =  (a,b) and  C = (c,d).

Their union is written as :   A ∪ C = (a,b) ∪ (c,d)

Now, if interval is written in form [a,b] ⇒  a and b are INCLUDED in interval

Also, if interval is written in form (a,b) ⇒  a and b are NOT INCLUDED in interval

Here, the given interval is [-2,6]

excluding 3 and 6 from this will give:

[-2,3)  ∪   (3,6)

The first set is [-2.3)   where  -2 is INCLUDED but 3 is NOT INCLUDED.

The second set is (3,6)   where 3 and 6 both are  NOT INCLUDED.

Hence,   [-2,6] - {3} - {6}  =   [-2,3)  ∪   (3,6)

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If it is rectangular or square then just multiply the length x width and you get the area (shaded area)
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