The display that would best show the measures of variation of the given prices is; B: Box and Whisker Plot
<h3>What is the importance of Box and Whisker Plot?</h3>
We are given the prices of Phone chargers in a store as;
$19, $18, $15, $17, $19, $12, $19, and $15.
Now, since we want to determine the display that would best show the measures of variation, the best display would be a box and whisker plot. This is because Box and Whisker plots are a great chart to use when showing the distribution of data points across a selected measure. These box and whisker plots display ranges within variables measured.
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Answer:
The data item is 
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 400 and a standard deviation of 60.
This means that 
z=3
We have to find X when Z = 3. So




The data item is 
Answer:

Step-by-step explanation:
The equations given are:


For the equations to generate the same independent value, then

This implies that:

Group similar terms to get:

Simplify to get:


Total weight of the 8 backpacks = 8 x 14 = 112 pounds
Total weight of the 12 backpacks = 12 x 9 = 108 pounds
Total weight of all the 20 backpacks = 220 pounds
Mean weight of the 20 backpacks = 220 ÷ 20 = 11 pounds
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Answer: The mean weight of the 20 backpacks is 11 pounds
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