B. Carbon dioxide bexause it is 96.5%
<span>Sm
For an element to have a partially filled f orbital, it will have to have an f orbital in the first place, this cancels barium, as it is the lightest of the elements listed:
Barium does not have an f orbital:
[Xe]6s^2
or
1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2
Sm:
[Xe] 4f6 6s2
Does have an f orbital AND they are partially filled (the F subshell has the potential to hold 14 electrons, but Sm only holds 6 electrons on its F subshell, therefore the electrons, by the rule of maximum multiplicity, in which the electrons will try to occupy orbitals by themselves first (the F subshell has 7 orbitals because 14/2 = 7), it leaves the f subshell with partially filled orbitals.
Os:
Xe 4f14 5d6 6s2
all occupied f orbitals
Bi:
Xe 4f14 5d10 6s2 6p3
Has full F orbitals </span>
sun‘s life cycle
1. nebula
2. protostar
3. sequence star (sun is this currently)
4. red giant
5. white dwarf
6. black dwarf
bigger stars
1. nebula
2. protostar
3. sequence star
4. red super giant
5. supernova
6a. black hole
or
6b. neutron star
Sun was a protostar
is currently a main sequence star
will remain so for another 4-5 billion years.
It will then expand and cool to become a red giant
after which it will shrink and heat up again to become a white dwarf
The white dwarf star will run out of nuclear fuel and
slowly cool down over many billions of years
black dwarf
BBC
https://www.bbc.co.uk/bitesize/guides/zwv8xfr/revision/1
Answer:
1.
work out the mean mode median and range
Explanation: