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mariarad [96]
3 years ago
9

Find quadratic equation having zeroes as -3/alpha and 2/alpha

Mathematics
1 answer:
Degger [83]3 years ago
3 0
(x-\frac{2}{\alpha})(x+\frac{3}{\alpha)}=x^{2}+\frac{x}{\alpha}-\frac{6}{\alpha^{2}}
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2 years ago
What is the answer for <br> -7+x/3=-13
Law Incorporation [45]

Answer:

x = - 18

Step-by-step explanation:

Given

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\frac{x}{3} = - 6 ( multiply both sides by 3 to clear the fraction )

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A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7 if you want to cooy back to its original size by what
slamgirl [31]

Answer:

1/7

Step-by-step explanation:

Given that:

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In other to obtain the original size of the rectangle, all that is needed is to multiply the sacl d dimension by the reciprocal of the initi. Scale factor used, that is 1 / 7

This gives :

(2 inches by 3 inches) * 1/7

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3 0
3 years ago
Write the function that shows a translation of f(x) two units to the left.
Galina-37 [17]

Answer:

Step-by-step explanation:

Suppose the base formula is y = x^2

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basically that is y = (x + 2)^2 just the opposite of what you might think it should be.

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Where does y = (x + 2)^2 have it's minimum?

(-2,0)

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3 0
3 years ago
A pair of equations is shown below:
Nina [5.8K]
Sorry I don't what the answer would be for A. But B would be (3,13)
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