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4 years ago

Find quadratic equation having zeroes as -3/alpha and 2/alpha

Mathematics

1 answer:

Degger [83]4 years ago

3 0

$(x-\frac{2}{\alpha})(x+\frac{3}{\alpha)}=x^{2}+\frac{x}{\alpha}-\frac{6}{\alpha^{2}}$

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A salesman makes both a base salary and also a commission, which is a percentage of what he sells. Each month, if his sales tota

ss7ja [257]

Linear equation is the equation in which the highest power of the unknown variable is one.

The given equation the constant 2000 represents the base salary or the fixed salary of the salesman.

To find that what does 2000 represent in the given linear equation we need to know about the linear equation.

<h3>What is linear equation?</h3>

Linear equation is the equation in which the highest power of the unknown variable is one.

Given information-

Total sales by salesman each month is $s$ dollars.

The total money made by the salesman each month by selling goods of $s$ dollars given by,

$S=2000+0.1s$

The above equation given in the problem is the linear equation. In this linear equation the salary of salesman depends on his sales.

The constant amount of $2000 is the fixed amount of the salesman.

The variable $s$ is the variable on which the salary of the salesman depends. Thus due to this variable the salary of the salesman changes.

Hence in the given equation the constant 2000 represents the base salary or the fixed salary of the salesman.

Learn more about the linear equation.

brainly.com/question/14323743

4 0

3 years ago

Will give brainlist<br>assignment name: solving triangles

Naddik [55]

I believe it would be three angles and one angle shown!

3 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

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5 0

3 years ago

Read 2 more answers

Which of the following is equivalent to In 4x+5inx-in2xy

marysya [2.9K]

I’m not seeing nothing

5 0

3 years ago

What are two possible FIRST STEPS to solve the equation below?<br> 3(x-5)=21

igomit [66]

Answer:

sorry i dont know

Step-by-step explanation:

but do the ones in the () first always

4 0

3 years ago