A local school held a charity coat drive for two months the school collected 269 coats in the first month 542 coats were collect
1 answer:
Answer:
School collected 273 coats in second month.
Step-by-step explanation:
Given
Total number of coats collected in 2 months = 542
Number of coats collected in first month = 269
We need to find the number of coat school collected in second month.
Solution:
Now we can say that;
Total number of coats collected in 2 months is sum of Number of coats collected in first month and Number of coats collected in Second month.
Also We can say that;
Number of coats collected in Second month is equal to Total number of coats collected in 2 months minus Number of coats collected in first month.
framing in equation form we get;
Number of coats collected in Second month =
Hence School collected 273 coats in second month.
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9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)
