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serious [3.7K]
4 years ago
7

Are these correct please help

Mathematics
2 answers:
Kazeer [188]4 years ago
7 0
The triangle has no obtuse angles and a right triangle only has 1 right angle
Rufina [12.5K]4 years ago
4 0
A triangle only has one right angle also the triangle has no obtuse angle.
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Can someone please explain how to solve these please!!!
Bumek [7]

Answer:

A= H<u>b B </u>

     2

Step-by-step explanation:

Q16- = A=75 cm

Q17- = A=10in

Q18- = A=70

4 0
3 years ago
Read 2 more answers
Determine whether the given value is a solution of the equation.
nlexa [21]

Answer:

16 is not the solution to the equation

Step-by-step explanation:

5 0
3 years ago
Find an equation of the line given one point and the slope. (–10, –5);
allochka39001 [22]
You forgot to provide the slope but here is how you do this 

the slope 5 = (y2 - y) / (x2 - x) but we know that (x2, y2) = (-10, -5)
=> (-5 - y) / (-10 - x) = 5 --- multiply both sides by (-10 - x)
=> (-5 - y) = 5 (-10 - x) 
=> (-5 - y) = -50 - (5)x --- add +5 to both sides 
=>  -y = (-50 + 5) - (5)x --- multiply both sides -1 
=> y = 5x + 45  --- this will be your equation. 
7 0
3 years ago
If im was born on june 9th of 1993 from 2015 she still alive how old is she now?
Vladimir79 [104]
If you're born on June 9th in 1993, on June 9th in 2015 you would have your 22nd birthday (2015-1993=22).

So you're 22 years old, and, as of today, 17 days tool (22 years 17 days).
7 0
3 years ago
Simplify. Your answer should contain only positive exponents with no fractional exponents in the denominator.
mart [117]

Answer:

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

Step-by-step explanation:

The given expression is  

\dfrac{3y^{\frac{1}{4}}}{4x^{-\frac{2}{3}}y^{\frac{3}{2}}\cdot 3y^{\frac{1}{2}}}

We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

\dfrac{3}{4\cdot 3}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{\frac{3}{2}+\frac{1}{2}}}    [\because a^ma^n=a^{m+n}]

\dfrac{1}{4}\cdot \dfrac{y^{\frac{1}{4}}}{x^{-\frac{2}{3}}y^{2}}

\dfrac{1}{4}\cdot \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{y^{2}}         [\because a^{-n}=\dfrac{1}{a^n}]

\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}

We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is \dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}.

5 0
3 years ago
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