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3 years ago

6

What is the length of segment A (2,1) B (6,6)

2 answers:

stepladder [879]3 years ago

4 0

4.7 because if you plug it in- (2,1) and (6,6) it is 4.7 units

ad-work [718]3 years ago

4 0

Distance formula : sqrt ((x2 - x1)^2 + (y2 - y1)^2)
(2,1)...x1 = 2 and y1 = 1
(6,6)...x2 = 6 and y2 = 6
time to sub and solve :)
d = sqrt ((6 - 2)^2 + (6 - 1)^2)
d = sqrt ((4^2) + (5^2))
d = sqrt (16 + 25)
d = sqrt 41
d = 6.40 <===

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Factor completely 3x^2 − 21

Firdavs [7]

The highest common factor of the two terms is 3, so that goes outside the bracket as 3(____). To get 3x^2, you multiply 3 by x^2, which is your first term in the bracket, and to get -21, you multiply 3 by -7, so your final answer is 3(x^2 - 7). I hope this helps!

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3 years ago

Read 2 more answers

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katrin [286]

Step-by-step explanation:

$3(2x - 5) = 6(x + 3)$

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3 0

3 years ago

Simplify the expression.<br> 7x2 + 3 - 5(x^2- 4)

polet [3.4K]

Answer:

2x² + 23

Step-by-step explanation:

Distribute the -5 and combine like terms.

7x² + 3 - 5(x² - 4) =

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3 0

3 years ago

What is the value of x and y when x = 9/4 and y = 3/5

zvonat [6]

Answer:

9/4 = 2.25 and 3/5=.6

Step-by-step explanation:

9/4 also equals 2 1/4'

6 0

3 years ago

D= V(x2 - 1)2 + (12 - y1)?

Mrac [35]

Answer:

The approximate length of segment EF is 7 unit

Step-by-step explanation:

Given figure is the graph having E and F coordinate

The coordinate of point E = ( $x_1$ , $y_1$ ) = ( - 2 , -4 )

The coordinate of point F = ( $x_2$ , $y_2$ ) = ( 2 , 2 )

Let The distance between the points E and F = D

So, D = $\sqrt{(x_2 - x_1)^{2} + ( y_2 - y_1 )^{2} }$

or, D = $\sqrt{(2 - (- 2 ))^{2} + ( 2 - ( - 4 ))^{2} }$

Or, D = $\sqrt{( 4 )^{2} + ( 6 )^{2} }$

or, D = $\sqrt{16 + 36}$

∴ D = $\sqrt{52}$

I.e D = 7.21 unit

So, Approximate value of D = 7 unit

Hence The approximate length of segment EF is 7 unit . Answer

8 0

3 years ago