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kotegsom [21]
3 years ago
12

Ms Melissa and Ms ryanne went for a walk and they got back at 8:02am their walk was actually 45 minutes what time did they leave

?​
Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer: 7: 17

Step-by-step explanation:

This doesn't really make sense but it's how I do it

8:02 = 7:62

    7:62

<u> -      45</u>

    7: 17

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What is equivalent to the expression: (10g^3 - 8g^2 + 5g - 14) + (10g^2 + 12g)
irinina [24]
10g^3 - 8g^2 + 5g - 14 + 10g^2 + 12g
its just a matter of combining like terms
10g^3 + 2g^2 + 17g - 14
5 0
3 years ago
Simplify 8/-3 ÷ -4/9<br><br> A. -8<br> B. -6<br> C. 6<br> D. 8
geniusboy [140]

Answer:

C. 6

Step-by-step explanation:

to divide by a fraction multiply by the recirpocal of that fraction.

8/3 ÷ 9/4

reduce the numbers with GCF 4 which equals 2/3 x 9

reduce the numbers with GCF 3 which equals 2x3= 6

4 0
2 years ago
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

3 0
3 years ago
A ball is kicked 4 feet above the ground with an initial vertical velocity of 51 feet per second. The function h(t)=−16t²+51t+4
uysha [10]

Answer:

0.6 seconds to 2.6 seconds

Step-by-step explanation:

From the graph the ball reaches 28 feet after 0.574 seconds

and doesn't fall below that until 2.614 seconds

0.574 rounded is 0.6 seconds

2.614 rounded is 2.6 seconds

4 0
2 years ago
Read 2 more answers
What is the square root of 504 simplified ?
Reil [10]

Answer:

6\sqrt{14}

Step-by-step Explanation:

     To simplify \sqrt{504}, we will look for numbers that 504 can be divided by until there are no perfect square roots under the radical.

[] To do this, we can think of perfect square roots such as 4, 9, 16, etc

We can divide 504 by 36 for an answer of 14, so \sqrt{504} can be written as \sqrt{36*14} which can be written as 6\sqrt{14} because the square root of 36 is 6.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

8 0
2 years ago
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