Answer:
Normal daughters and Hemophiliac son
Explanation:
Females exhibit hemophilia and colorblindness in homozygous genotype only.
The genotype of hemophiliac woman= X^hX^h
The genotype of colorblind man= X^cY
A cross between X^hX^h and X^cY would produce progeny in the following phenotype ratio= 1 Normal but carrier daughters:1 Hemophiliac son
Answer:
A
Explanation:
bc it says it................
Answer:
Since cell division occurs twice during meiosis, one starting cell can produce four gametes (eggs or sperm). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase
Explanation:
Answer: hello some details relating to your question is missing below is the missing detail
DNA Sequence= 3’ - TACTAGTTGTGCATT - 5’
Complementary Sequence=5`-ATGATCAACACGTAA-3`
Answer : MINT
Explanation:
The protein ( sequence of amino acids ) that resulted from your Translation is MINT
The m-RNA Produced form the information above is:
5`-AUGAUCAACACGUAA-3`
While the Protein Sequence is Met-Ile-Asn-Thr which can be written as MINT
