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3 years ago

What is the expanded form of the expression 3 sigma i^3 i=0

Mathematics

2 answers:

Naddik [55]3 years ago

5 0

Answer:

\bf \sum\limits_{i=0}^{3}~i^3\qquad \implies\qquad \stackrel{i=0}{0^3}~~+~~\stackrel{i=1}{1^3}~~+~~\stackrel{i=2}{2^3}~~+~~\stackrel{i=3}{3^3}

Step-by-step explanation:

Savatey [412]3 years ago

3 0

$\bf \sum\limits_{i=0}^{3}~i^3\qquad \implies\qquad \stackrel{i=0}{0^3}~~+~~\stackrel{i=1}{1^3}~~+~~\stackrel{i=2}{2^3}~~+~~\stackrel{i=3}{3^3}$

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1. A tank is 3/5 full of water. After 330 litres of water is drawn out, it becomes 2/7 full. Find the capacity of the tank in li

Andreas93 [3]

Answer:

1050

Step-by-step explanation:

Let x = full capacity

$\frac{3}{5} x=\frac{2}{7} x+330$

Move the variable to the left side by subtracting both sides by $\frac{2}{7} x$

$\frac{3}{5} x-\frac{2}{7}x=\frac{2}{7} x+330 -\frac{2}{7}x$

$\frac{3}{5} x-\frac{2}{7} x=330$

Combine the like terms (don't forget about common denominator)

$\frac{21}{35} x-\frac{10}{35} x=330$

$\frac{11}{35} x=330$

Multiply both sides by $\frac{35}{11}$ to isolate the x

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5 0

3 years ago

0.4x - 0.3 = -0.14 Need help, rush not needed

never [62]

This is a two step equation. What we want to do is get x by itself.

We will add .3 to both sides:
0.4x=-0.11

We will now divide both sides by .4

X=-0.275

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3 years ago

Give the following number in Base 16 NO LINKS!!!

olga nikolaevna [1]

Answer:

$\large{\boxed{35_{10} = \sf 23_{16}}}$

Explanation:

$\sf Given : 35_{10}$

Compute:

35 ÷ 16 = 2.1875 = 2R3

2 ÷ 16 = 0.125 = 0R2

Jot down the remainders:

3 ↑

2 ↑

======

$\sf Answer : \ 35_{10} = 23_{16}$

$\hrulefill$

Let's look at another example: $\sf 325_{10} = [?]_{16}$

Compute:

325 ÷ 16 = 20.3125 = 20R5

20 ÷ 16 = 1.25 = 1R4

1 ÷ 16 = 0.0625 = 0R1

Jot down remainders:

5 ↑

4 ↑

1 ↑

=====

$\sf 325_{10} = [145]_{16}$

$\hrulefill$

Another example: $\sf 500_{10} = [?]_{15}$

Compute:

500 ÷ 15 = 33.33... = 33R5

33 ÷ 15 = 2.2 = 2R3

2 ÷ 15 = 0.13... = 0R2

Jot down remainders:

5 ↑

3 ↑

2 ↑

=====

$\sf 500_{10} = [235]_{15}$

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