Please help on this one?

(0,5) and (-5,1)<br> write a linear equation

tensa zangetsu [6.8K]

Answer:

y=4/5x+5

Step-by-step explanation:

because this is the answer

5 0

1 year ago

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Azizah got 1 for the slope of the line through 2 points (1,2) and (4,-1). Explain to her the mistake she made and how to find th

ololo11 [35]

(1,2)(4,-1)
slope = (y2 - y1) / (x2 - x1)
slope = (-1 - 2) / (4 - 1) = -3/3 = -1

the slope is -1......I am not sure of the mistake.....unless she just added (-1 - 2) and got 3 instead of -3.......or when dividing -3/3....she maybe forgot about the negative sign

5 0

2 years ago

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(05.01) Which statement best describes the area of the triangle shown below?

alukav5142 [94]

Answer:

A

Step-by-step explanation:

Area of a triangle:

$A=\frac{b*h}{2}$

In our case:

b=4

h=2

Plug in what we know:

$A=\frac{(4)(2)}{2} \\A=4units$

Find the matching solution:

A.) it is 1/2 the area of a rectangle of length 4 units and width 2 units

X B.) it is twice the area of a rectangle of length 4 units and width two units

X C.) it is 1/2 the area of a square of side length 4 units

X D.) it is twice the area of a square of side length 4 units

6 0

1 year ago

F(x) = (3x + 6) (x - 3)²

Sever21 [200]

f(x)= 3x³ - 18x +9

Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.

Identity I: (a + b)² = a² + 2ab + b²

Identity II: (a – b)² = a² – 2ab + b²

Identity III: a² – b²= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x² + (a + b) x + ab

Identity V: (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

Identity VI: (a + b)³ = a³ + b³ + 3ab (a + b)

Identity VII: (a – b)³ = a³ – b³ – 3ab (a – b)

Identity VIII: a³ + b³ + c³ – 3abc = (a + b + c)(a² + b² + c² – ab – bc – ca)

f(x) = (3x + 6) (x - 3)²

= ( 3x + 6) ( x - 3 )²

= ( 3x + 6)( x² - 6x + 9)

= 3x( x² - 6x + 9) + 6( x² - 6x + 9)

= 3x³ - 6x² + 18x + 6x² - 36x +9

= 3x³ - 18x +9

To learn more about algebraic expansions, refer to brainly.com/question/4344214

#SPJ9

5 0

1 year ago

Match the y-coordinate with the given x-coordinate for the equation y = log10x.

Andrew [12]

The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:

$For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.$

We know that the equations is:

$y=log(10x)$

So let's solve each case:

Case 1

$x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}$

Case 2

$x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}$

Case 3

$x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}$

Case 4

$x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}$

Case 5

$x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}$

5 0

3 years ago

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