1+cosx/1-cosx=tan^2x/(sec^2-1)^2
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Answer:
The function of height has a maximum value.
Step-by-step explanation:
Maximum or Minimum:
A given function f(x).
- Find out f'(x) and f''(x)
- Then set f'(x)=0 which gives x=a.
- f''(a) > 0 , then at x=a , f(x) has minimum value.
- If f''(a)<0 , then at x=a, f(x) has maximum value.
Given that, a baseball is thrown with with an velocity of 32 feet per second.
The equation of height is
Differentiating with respect to t
Again differentiating with respect to t
Next, we set h'=0
Now
Since at t=1, h''<0.
The function of height has a maximum value.
The maximum of h is = -16.(1)²+32
= -16+32
=16 feet