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matrenka [14]
3 years ago
11

Jim put $750 in a savings account that pays 7.75% simple interest. How much will he have at the end of 2 years?

Mathematics
1 answer:
Stella [2.4K]3 years ago
6 0
He will have $870.7546875
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The Pie Factory sells an apple pie with a diameter of 16 inches for $10.99. What is the approximate cost per square inch of surf
hammer [34]
I believe the answer is 0.05
not sure though.

6 0
3 years ago
Olivia is on a road trip with her family. During a three- hour stretch,they traveled 183 miles.How fast were they driving in mil
77julia77 [94]

183/3 = 61

They drove 61mph.

8 0
4 years ago
List two numbers that are between the two given numbers:<br> 2 3/5 and 2 7/10
Arisa [49]

Answer:

There are many choices, but one answer is 2 3.1/5 and 2 3.2/5.

Step-by-step explanation:

These are equivalent to 2 6.2/10 and 2 6.4/10 which is between both.

(pls mark as brainliest!)

3 0
3 years ago
Some parts of California are particularly earthquake-prone. Suppose that in one metropolitan area, 32% of all homeowners are ins
Bumek [7]

Answer:

P(X = 0) = 0.2138

P(X = 1) = 0.4025

P(X = 2) = 0.2841

P(X = 3) = 0.0891

P(X = 4) = 0.0105

Step-by-step explanation:

For each homeowner, there are only two possible outcomes. Either they have invested in earthquake insurance, or they have not. The probability of a home owner having invested in earthquake insurance is independent from other homeowners. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

32% of all homeowners are insured against earthquake damage.

This means that p = 0.32

Four homeowners are to be selected at random.

This means that n = 4

Find the probability distribution of X.

This is the probability of each outcome

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{4,0}.(0.32)^{0}.(0.68)^{4} = 0.2138

P(X = 1) = C_{4,1}.(0.32)^{1}.(0.68)^{3} = 0.4025

P(X = 2) = C_{4,2}.(0.32)^{2}.(0.68)^{2} = 0.2841

P(X = 3) = C_{4,3}.(0.32)^{3}.(0.68)^{1} = 0.0891

P(X = 4) = C_{4,4}.(0.32)^{4}.(0.68)^{0} = 0.0105

6 0
3 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
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