Hello there.
Question: <span>Jamie has a deck of 60 sports cards, of which some are baseball cards and some are football cards. Jamie pulls out a card randomly from the deck, records its type, and replaces it in the deck. Jamie has already recorded six baseball cards and nine football cards. Based on these data, what is, most likely, the number of baseball cards in the deck?
12
15
24
30
Answer: You could use ratio to figure this out.
6:9 = 15
6 baseball for 9 football cards
Divide the total by the amount already known
60/15 = 4
Multiply all values by 4.
6 x 4 = 24.
9 x 4 = 36.
In short, the answer is 24.
Hope This Helps You!
Good Luck Studying ^-^
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Answer:
oki! Mizuki here to help! 12 will be your answer!
Step-by-step explanation:
Soo... The ratio of blue to green is 4:3 right?
and there are 21 balloons!
4 + 3 is 7! So we divide 21 by 7 and get 3!
Then we multiply 3 by the number of blue balloons(aka 4) and get 12!
Answer:
6:15 and 8:20 are examples of additional equivalent ratios.
Step-by-step explanation:
The table is:
<u>Books (x) Cost (y)</u>
2 5
4 10
From the table, the ratio Books : Cost is 2:5 or 4:10. Equivalent ratios are obtained, using a graph, from the plot of the line that pass through these two points. In the figure attached, this line is shown. There, it can be seen that ratios 6:15 and 8:20 are equivalent to those from the table.
We have been given that Jackson purchases a new car for $48,000. The car's value can be modeled by the following exponential function: 
where y represents the car's value and t represents time in years. We are asked to find the decay rate as a percentage.
We know that an exponential decay function is in form 
, where,
y = Final value,
a = Initial value,
r = Decay rate in decimal form,
x = time.
Upon comparing our given function with standard decay function , we can see that 
.
Let us solve for r.
Let us convert 0.24 into percentage.
Therefore, the decay rate is 24%.
Step-by-step explanation:
∫₀² x f(x²) dx
If u = x², then du = 2x dx, and ½ du = x dx.
When x = 0, u = 0. When x = 2, u = 4.
∫₀⁴ ½ f(u) du
½ (16)
8
