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const2013 [10]
3 years ago
7

(PLEASE ANSWER: TIMED)The intensity, or loudness, of a sound can be measured in decibels (dB), according to the equation I(dB)=1

0log[1/10], where I &/ the intensity of a given sound and I0 is the threshold of a hearing intensity. What is the intensity, in decibles, [I(dB)], when I=10^8(I0)? Round to the nearest whole number.
(Refer to photo for equations)
A.8
B.9
C.19
D.80

Mathematics
2 answers:
mixas84 [53]3 years ago
7 0

Answer:

D) 80

Step-by-step explanation:

Mrac [35]3 years ago
3 0
For this case we have the following equation:
 l(dB) = 10log( \frac{l}{lo} )
 We must replace the following value in the equation:
 l = 10^8lo
 Substituting we have:
 l(dB) = 10log( \frac{10^8lo}{lo} )
 Simplifying the given expression we have:
 l(dB) = 10log(10^8)
 Then, using logarithm properties in base 10, we can rewrite the expression:
 l(dB) = 10(8)
 Finally, making the product, the result is:
 l(dB) = 80
 Answer:
 
l(dB) = 80
 option 4
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Solving systems of equations using substitution p=q+2<br> 4p+3q= -27
GREYUIT [131]
Ok, so you are given the value of P=q+2

The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27


Doing so will give us 4(q+2)+3q= -27

For right now, lets just focus on the first part, 4(q+2)

We can simplify this by distributing(multiplying) the 4 to whats inside the variables.

This will give us 4q+8

now lets add this back to the rest of the equation >>>  4q+8+3q = -27

We can further simplify by adding like terms >>> 7q+8 = -27

subtract the 8 from both sides >>> 7q = -35

now divide both sides by 7 >>> q = -35/7

Therefor q = -5

EDIT* 

now that we know q = -5 we can put q into the equation for P !

we know that p=q+2

so lets put q in now >>> p=(-5)+2

and simplify>>> p = -3

I hope this helps:)
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