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AveGali [126]
3 years ago
12

Please help me, please?

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0

The answer is 14 2/3

I hoped this helped youuuuu!!!!!

pickupchik [31]3 years ago
3 0
Omar can make 14 whole dumplings. You change 2 3/4 cups to an improper fraction (multiply the denominator and the numerator) and you get 11/4. Since you need 3/16 cups for One dumpling you have to find the greatest common denominator which is 16. You multiply by 4 by 11 to get the numerator and end up with 44/16. Since you need 3/16 for 1 whole dumpling you divide 44 by 3 and get 14.6 repeating. You cannot have a fraction of a dumpling so you round down and get the answer 14.
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The empty set is the special set that contains no (i.e., zero) elements in the set. We use the notation empty set to represent t
Minchanka [31]

Answer:

The value of a Cartesian product between an empty set and set A is equal to the empty set.

Step-by-step explanation:

The cartesian product is given by:

A×B= {(a,b): a∈A, b∈B}

This means that each element of set A is combined with an element of set B.

The empty set is the unique set having no elements and its size is zero.

Let Ф be the empty set and let A be a set of elements chosen from U.

A×Ф=Ф

Since the empty set has no elements, no ordered pairs can be formed and the result is the empty set.

5 0
3 years ago
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass
Tju [1.3M]

Answer:

6.56 g

Step-by-step explanation:

We can write the mass of radioactive isotope left after a time t by using the equation

N(t)=N_0 (\frac{1}{2})^{\frac{t}{t_{1/2}}}

where

N_0 = 210 g is the initial amount of radioactive isotope

t_{1/2} is the half-life

t is the time

In this problem, we want to know the amount of radioactive isotope left after 5 half-lives, so after

t=5 t_{1/2}

Substituting into the equation, we have

N(t)=(210 g) (\frac{1}{2})^{\frac{5 t_{1/2}}{t_{1/2}}}=\frac{210 g}{2^5}=6.56 g

5 0
3 years ago
What is the slope intercept equation of the line below?
antoniya [11.8K]

Answer:

{ \tt{slope, \: m =  \frac{1 - ( - 1)}{1 - 0} }} \\m  = 2 \\ y - intercept : y = mx + c \\ { \tt{1 = (2 \times 1) + c}} \\ c =  - 1 \\ { \boxed{ \bf{y = 2x - 1}}}

5 0
3 years ago
I need help on number 6
sergeinik [125]
D is correct
3(2x-5)=6x+k
6x-15=6x+k
If 2 equations are identical the solution will be infinite
4 0
3 years ago
Place the indicated product in the proper location on the grid. (4x^3+7y^3 z^ 4) ^2
ella [17]

Answer:

16x^{6} +56x^{3}y^{3} z^{4} +49y^{6} z^{8} \\

Step-by-step explanation:

To solve this type of problems first need to review some laws of exponents:

When you are multiplying the same base, you need to add the exponents.

x^{2} +x^{8}  = x^{2+8}  = x^{10}

When you are raising a base with power to another power, you should keep the base and multiply the exponents:

(x^{2} y^{5})^3 = x^{2*3} y^{5*3} = x^{6} y^{15}

Now for the expression (4x^{3} + 7y^{3} z^{4} )^2

Write the multiplying factors:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} )

Multiply the term 4x^{3}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}

Then multiply the term 7y^{3}z^{4}

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{3+3} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{3+3} z^{4+4}

Simplify the exponents:

(4x^{3} + 7y^{3} z^{4} )(4x^{3} + 7y^{3} z^{4} ) = 16x^{6} + 28x^3y^{3} z^{4}\\\\+ 28x^3y^{3} z^{4} + 49y^{6} z^{8}

Add like terms:

= 16x^{6} + 56x^3y^{3} z^{4} + 49y^{6} z^{8}

5 0
3 years ago
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