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DiKsa [7]
2 years ago
10

BONUS!

Mathematics
1 answer:
Nitella [24]2 years ago
3 0
The answer is gonna be 14
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For the members of a neighborhood meeting group, the probability of randomly selecting a member who likes to cook is 42%, the pr
Monica [59]

Answer: Probability of randomly selecting a member who likes to cook or likes to sew = 58%

Step-by-step explanation:

Since we have given that

Probability of a randomly selecting a member who likes to cook=P(C) = 42%

Probability of a randomly selecting a member who likes to sew =P(S)= 23%

Probability of a randomly selecting a member who likes to both cook and sew

P(C\cap S)=7\%

As we know the "Probability rules " :

P(C\cup S)=P(C)+P(S)-P(S\cap C)\\\\P(C\cup S)=42+23-7\\\\P(C\cup S)=58

So, Probability of randomly selecting a member who likes to cook or likes to sew = 58%



5 0
3 years ago
A baseball team played 154 regular season games. The ratio of the number of games they won to the number of games they lost was
Fittoniya [83]

Answer:

88 won and 66 lost

Step-by-step explanation:

Won = \frac{154}{4+3}×4 = 88 games

Lost = 154 - 88 = 66 games

7 0
3 years ago
What does 4+9n mean
vlabodo [156]
You have to add 4 and 9 then drop your variable
4 0
3 years ago
HELP THIS IS DUE SOON!<br><br> find the error!
Rudik [331]

Answer:

Step 1

Step-by-step explanation:

they were supposed to multiply 2x by 4 and -1 by 4 but they only multiplied 2x by 4.

3 0
2 years ago
Read 2 more answers
B A pair of fair dice is rolled, If the sum of the spots is 7, determine the probability that one di showed a 2.
finlep [7]

Answer:

\text{Probability}=\frac{1}{3}

Step-by-step explanation:

Given : A pair of fair dice is rolled, If the sum of the spots is 7.

To find : Determine the probability that one die showed a 2 ?

Solution :

A pair of fair dice is rolled the outcomes are,

(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

The sum of the spots is 7 i.e. (4,3),(2,5),(5,2),(3,4),(1,6),(6,1).

Total possibility = 6

Favorable outcome is that one die showed a 2 i.e. (2,5),(5,2)= 2

The probability that one die showed a 2 is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}

\text{Probability}=\frac{2}{6}

\text{Probability}=\frac{1}{3}

8 0
2 years ago
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