Refer to the attached image.
Let the height of the Empire State Building = BC = 'x'
John is standing at distance from Empire State Building = AB = 1 mile
The angle of elevation = 11°
In triangle ABC,
Consider 



x = 0.194 mile
Since 1 mile =5280 feet
So, x = 
= 1024.32 feet.
So, the height of the Empire State Building is 1024.32 feet.
I can’t help don’t have any question and photo
Answer:

Step-by-step explanation:
Given
Co ordinates of vertices(1,-6) and (-8,-6)
When two points is given then Length of two points is given by



Perimeter of rectangle is =26 units
Let the other side be x
thus

x+9=13
x=4 units
therefore to get the other two co ordinates
such that the length of that side is 4 units is


Horizontal distance will remain same only vertical distance will change in given co ordinates to obtain the remaining two co ordinates
To verify the above two distance between two points must be 13 units
-5x - 7 < 28.....add 7 to both sides
-5x < 35....divide both sides by -5, change the inequality sign (u change the inequality sign when dividing/multiplying by a negative number)
x > -7
Density=mass/volume
given mass=120g and volume=200cm3
density=

or abot 0.6
the density is