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Pavlova-9 [17]
3 years ago
6

After a customer buys a computer or receives service from Top Computers and Service, a service representative contacts each cust

omer to conduct a survey. The survey information is a form of output.a. Trueb. False
Computers and Technology
1 answer:
Crank3 years ago
4 0
The answer is A. True
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Which of the following statements is false? a. All arguments in Java are passed by value. b. When an argument is passed by refer
Kruka [31]

Answer: (B) When an argument is passed by reference, the called method can access the argument’s value in the caller directly but cannot modify it.

Explanation:

  In call by reference method, when an argument is pass to the function so that it copies an argument in the form of formal parameter. In the function, the reference is basically used for accessing the actual argument in the given call function value.

The function is basically operated on the given argument value and the original value gets change when the given function value change the value of argument when it is pass by reference method.

6 0
3 years ago
Which statement is correct in the screenshot attached?​
Artemon [7]

Answer:

answering

Explanation:

A is right hope you do good

8 0
3 years ago
To have the most impact when using email you should structure your message so that
VladimirAG [237]
It catches the readers attention making them respond to you quicker 
7 0
3 years ago
Subtract the following the Hex numbers:<br><br> 67h<br><br> 2Ah<br><br> Result is =
-BARSIC- [3]

Answer:

3D ( in hexadecimal )

Explanation:

Converting the given hexadecimal numbers to decimal:

 67 (HEX) = 16*6 + 7 = 103 (Decimal)

 2A (HEX) = 2*16 + 10 = 42 (Decimal)

Subtracting the two numbers: 103 - 42 = 61 (Decimal)

Converting the result to Hexadecimal format:

61 = 16* 3 + 13

13 corresponds to D in hexadecimal.

So result in hex is 3D.

To summarize, the subtraction result for the two given hexadecimal numbers is 61 in decimal format or 3D in hexadecimal.

4 0
4 years ago
Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m
shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

 

def getName(self):

 

return self.name

 

def setScore(self, i, score):

 

self.scores[i - 1] = score

 

def getScore(self, i):

 

return self.scores[i - 1]

 

def getAverage(self):

 

return sum(self.scores) / len(self._scores)

 

def getHighScore(self):

 

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

 

def __ge__(self,student):

return self.name == student.name or self.name>student.name

 

def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

 

 

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

 

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

5 0
4 years ago
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