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3 years ago

PLZ HELP ME!!! which expression represents the area of the storage facility in square feet?

Mathematics

1 answer:

WITCHER [35]3 years ago

7 0

Area = (5x + 4)(4x - 4)
= 20x^2 - 20x + 16x - 16
= 20x^2 - 4x - 16 Answer

Its G

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Please, Need Help ASAP!!

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2 years ago

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Any time a scientific theory is challenged it means it's not a good theory. Why?

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If a theory is challenged, then that means that the theory may have a specific flaw, making it "not good"

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3 years ago

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1. The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest

kaheart [24]

Answer:

(a). Weight of the bag of organic apples for advertising = 5 pound

Cost of the advertisement of 5 pound bag of organic apples = $13.95

Now, to find the unit rates :

Cost of advertising 5 pound bag of organic apple = $13.95

$\text{Cost of advertising 1 pound bag of organic apple = }\frac{13.95}{5}=\$2.79$

Hence, unit rate of advertising 1 pound of organic apples = $2.79

$13.95 is charged for advertisement of 5 pound of organic apples

$\$\text{1 will be charged for advertisement of }\frac{5}{13.95}=0.36\text{ pounds}$

Hence, one unit or $1 is charged for advertisement of 0.36 pounds of organic apples.

(b) Cost of 5 pound is given to be $13.95

So, the rate which is typically used in the given problem is : Dollars per pound.

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3 years ago

Find the area of the surface. the part of the hyperbolic paraboloid z = y2 â x2 that lies between the cylinders x2 + y2 = 4 and

lukranit [14]

$x=u\cos v,y=u\sin v\implies z=u^2\sin^2v-u^2\cos^2v=-u\cos2v$

$\mathbf s(u,v)=\langle u\cos v,u\sin v,-u\cos2v\rangle$

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

$\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=2}^{u=5}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv=\dfrac{(101^{3/2}-17^{3/2})\pi}6$

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3 years ago

I really need some help please

hichkok12 [17]

Answer:

(1, - 1 ) and (5, - 3 )

Step-by-step explanation:

To determine which points are solutions of the inequality.

Substitute the x/y values into the left side of the inequality and compare with the right side.

(- 6, - 3)

- 3 + 12 = 9 > - 3 ← not a solution

(1, - 1 )

- 1 - 2 = - 3 ≤ -3 ← this is a solution

(5, - 3 )

- 3 - 10 = - 13 < - 3 ← this is a solution

(0, - 2 )

- 2 - 0 = - 2 > - 3 ← not a solution

(7, 12 )

12 - 14 = - 2 > - 3 ← not a solution

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3 years ago