Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron
Answer:
The question has some probable errors, but I will illustrate how to solve a problem such as this.
Explanation:
The speed of a wave is given by Speed = (Distance)/(Time), or, alternatively, Speed = Wavelength x Wave Frequency
In this problem, we are given a speed of "3 x 10 m/s." I suspect that the speed should have read 3x10^8 m/s, the speed of light. This says the speed is 30 m/s.
The frequency reads "998 x 10% H2." I can't guess what this was supposed to be, but 998 x 10% H2 means "99.8 H2." That doesn't seem to have anything to do with wavelength. Find the correct frequency, plug it into the equation with the correct speed, such as:
3x10^8 m/s = (9.98x10^2 cycles/sec)(Wavelength)
Wavelength = (3x10^8 m/s)/((9.98x10^2 cycles/sec) = 3.01x10^5 meters
Use the correct numbers, and you should be able to calculate the correct wavelength.
The calculated mutual inductance is 8.544 x 10⁻⁵ H.
Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.
Length of the solenoid= 5.0 cm
Area of cross-section=1.0 cm²
no of spaced turns=300 turns
turns of insulated wire=180 turns
Mutual inductance (M) = μ₀μr N1N2 A/ L
=(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5
=79.12 x 10⁻¹⁰ x 54000 / 5
=8.544 x 10⁻⁵ H
hence, the mutual inductance is 8.544 x 10⁻⁵ H.
Learn more about Mutual inductance here-
brainly.com/question/14014588
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