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3 years ago

Which statement best describes Gay-Lussac’s law?

Physics

2 answers:

gtnhenbr [62]3 years ago

6 0

The answer is D. Pressure is directly proportional to temp

prohojiy [21]3 years ago

6 0

D. lllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllll

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Until he was in his seventies, Henri LaMothe excited audiences by belly-flopping from a height of 9 m into 32 cm. of water. Assu

baherus [9]

Answer:

823.46 kgm/s

Explanation:

At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.

So, mgh = 1/2mv²

From here, his velocity just as he reaches the surface of the water is

v = √2gh

h = 9 m and g = 9.8 m/s²

v = √(2 × 9 × 9.8) m/s

v = √176.4 m/s

v₁ = 13.28 m/s

So his velocity just as he reaches the surface of the water is 13.28 m/s.

Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.

So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.

His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,

J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s

So the magnitude of the impulse J of the water on him is 823.46 kgm/s

6 0

3 years ago

Two automobiles of equal mass approach an intersection. One vehicle is traveling with speed 13.0 m/s toward the east, and the ot

puteri [66]

Answer:

Explanation:

We shall apply law of conservation of momentum to know the Speed of northward moving vehicle before collision to check the veracity of driver's statement .

Let v be the velocity of composite mass after collision

Applying law of conservation of momentum in north direction

m v₂ = 2m v sin55.08

Applying law of conservation of momentum in east direction

m x 13 = 2m v cos55.08

Dividing these two equations

v₂ / 13 = tan55.08

v₂ = 13 tan55.08

= 18.62 m/s

= (18.62 x60 x 60) / 1000

= 67 km/h

= 67 x 5/8 mi/h

= 42 mi/h

So he is lieing.

7 0

4 years ago

Please help.

Alex787 [66]

Explanation:

mathematically,

$kinetic \: energy \: = \frac{1}{2} m {v}^{2}$

where m= mass

and v=velocity

given that,

kinetic energy=493900J

mass =5040kg

making velocity the subject

$v = \sqrt{ \frac{2 \times kinetic \: energy}{mass} }$

substitute their values in the formula

$v = \sqrt{ \frac{2 \times 493900}{5040} }$

$v = \sqrt{ \frac{987800}{5040} }$

$v = \sqrt{196}$

$v = 14m {s}^{ - 1}$

Thus the velocity is 14meters per second

6 0

3 years ago

Which of these is true about a magnetic field?

dimulka [17.4K]

The answer is It points in the same direction as it would make a compass point. In a magnetic field, the direction of the magnetic field at any location is described as the direction in which the north pole of a compass needle points at that location.

6 0

4 years ago

Force

dezoksy [38]

Answer:

Answer is a force liquid that cannot be compresed

on edgenuity

Explanation:

3 0

3 years ago