Question

A 7.9 g bullet leaves the muzzle of a rifle with ayvaci (na25565) – Chapter 4 Basics – balantic – (APPhysPd4Balant) 2 a speed of 443.4 m/s. What constant force is exerted on the bullet while it is traveling down the 0.7 m length of the barrel of the rifle? Answer in units of N.

Answer 1

Answer:

$1109.41$ N

Explanation:

$v_{o}$ = initial velocity of the bullet = 0 m/s

$v_{f}$ = final velocity of the bullet as it leaves  = 443.4 m/s

$a$ = acceleration of the bullet

$d$ = length of the barrel of the rifle = 0.7 m

the kinematics equation we can use must include the variables in the above list, hence

${v_{f}}^{2} = {v_{o}}^{2} + 2 a d$

${443.4}^{2} = {0}^{2} + 2 (0.7)a$

$a = 140431.11$ ms⁻²

$m$ = mass of the bullet = 7.9 g = 0.0079 kg

Force exerted on the bullet is given as

$F = ma$

$F = (0.0079)(140431.11)$

$F = 1109.41$ N