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Blizzard [7]
3 years ago
10

When monochromatic light is incident for a short period of time on a thin barrier having two slits, how will a screen placed in

front of the slits appear?
Physics
2 answers:
e-lub [12.9K]3 years ago
8 0
If your on Plato it's E
BartSMP [9]3 years ago
7 0

Answer:

Interference pattern- alternate bright and dark fringes

Explanation:

When a monochromatic light is incident on a thin barrier having two slits, an interference pattern can be observed.

Dark and bright fringes would appear on the screen placed in front of it. It would not be random pattern. It would be a smooth pattern with distinctive dark fringe and bright fringe alternatively.

When the light from two source would superimpose, a constructive interference would lead to bright fringe and destructive interference would lead to dark fringe.

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VMariaS [17]

Answer:

Ted is correct

Explanation:

The equation for gravitational potential energy is PE = m·g·h

The equation for gravitational kinetic energy is KE = 1/2·m·v²

Where:

m = Mass of the object (The racing car)

g = Acceleration due to gravity

h = The height to which the object is raised

v = Velocity of motion of the object

From the principle of conservation of energy, energy can neither be created nor destroyed but changes from one form to another, we have;

Potential energy gained from location at height h = Kinetic energy gained as the object moves down the level ground

m·g·h = 1/2·m·v² canceling like terms gives

g·h = 1/2·v²

v = (√2·g·h)

If the speed is doubled, we have

2·v = 2× (√2·g·h) =  (√2·g·4·h)

Therefore, if 2·v = v₂ then v₂ =  (√2·g·4·h)

Since g, the acceleration due to gravity, is constant, it means that the initial  height must be multiplied or increased 4 times to get the new height, that is we have;

v₂ =  (√2·g·4·h) = (√2·g·h₂)

Where:

4·h = h₂

Which gives;

v₂² = 2·g·h₂

1/2·v₂² = g·h₂

1/2·m·v₂² = m·g·h₂ Just like in the first relation

Therefore, Ted is correct s they need to go up four times the initial height to double the speed.

5 0
3 years ago
A merry-go-round makes one complete revolution in 5.3 s. A 48.5 kg child sits on the horizontal floor of the merry-go-round 2.7
Marianna [84]

Answer:183.94 N

Explanation:

Given

Time Period T=5.3 s

mass of child m=48.5 kg

Radius r=2.7 m

Velocity v=\frac{2\pi \cdot r}{T}

v=\frac{2\pi \cdot 2.7}{5.3}

v=3.20 m/s

Now Centripetal Force will be Balanced by Frictional Force

Centripetal Force F_c=m\cdot \frac{v^2}{r}

F_c=48.5\cdot \frac{3.2^2}{2.7}

F_c=183.94 N

therefore Friction Force is 183.94 N

4 0
3 years ago
ASAP is the object of soccer ??????
n200080 [17]
Soccer is a sport that has offense, people in the middle, and defense. The goal to playing soccer is to get past the defenders by using teamwork and score more goals than the other team to win.
6 0
3 years ago
Do magnets have to touch each other in order to experience a magnetic force ?
Serjik [45]

Answer:

no

Explanation:

5 0
4 years ago
Read 2 more answers
A spider is crawling on a wall. First it crawls 1 meter up, then 1 meter to the left, and then 1 meter down. what is its total d
maria [59]
1 meter up, 1 meter to the left and then 1 metter down.
It goes 1 meter up and 1 meter down, so its in the same place. The only displacement is 1 meter to the left.

Look at picture:

(hope this helps)

4 0
3 years ago
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