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bogdanovich [222]
3 years ago
15

What is the value of c in the equation? 15.3 = StartFraction c Over 2.1 EndFraction 13.2 17.4 32.13 321.3

Mathematics
2 answers:
harina [27]3 years ago
3 0

Answer:

32.13

Step-by-step explanation:

15.3= c/2.1

c= 15.3* 2.1

c= 32.13

Makovka662 [10]3 years ago
3 0

Answer:

32.13

Step-by-step explanation:

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PLS HELP! WILL GIVE BRAINLIEST
Leviafan [203]

Answer:

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Step-by-step explanation:

<u>The standard form of the equation of a circle is: </u>

  • ( x - h )^2 + ( y - k )^2 = r^2, where ( h, k ) is the center and r is the radius

<u>Rewrite the given equation in the standard form:</u>

  • 2x^2 + 2y^2 - 8x + 10y + 2 = 0
  • x^2 - 4x + y^2 + 5y = -1
  • x^2 - 4x + 2^2 + y^2 + 5y + (5/2)^2 = -1 + 4 + 25/4
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<u>The center is:</u>

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<u>And radius is:</u>

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4 0
3 years ago
Could someone show me how to multiply these
mel-nik [20]

Answer:

A.2304

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Step-by-step explanation:

The easiest way to show you is by using calculator. If you can't, try  using Khan Academy if you want.

6 0
3 years ago
(2.1 x 104) + (3.5 x 106)
igor_vitrenko [27]

Answer:

the answer is 589.4

Step-by-step explanation:

In doing this equation you do the order of operations:

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you then add the answers together to get:

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8 0
3 years ago
If the rate of change (ROC) of the function is quadratic, what is the function type ? Choose the correct answer.
evablogger [386]

If the rate of change (ROC) of the function is quadratic, then the function type is cubic

<h3>What is rate of change?</h3>

The rate of change of a function is the rate at which the output values change over the input value

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This means that, a cubic function will have a quadratic rate of change

Hence, the correct option is (d)

Read more about rate of change at:

brainly.com/question/8728504

4 0
3 years ago
If the sin 90° = 1, then the cos 0° = _____. (1 point)
Cloud [144]
<span>sin 90° = 1
</span>
cos 0° = 1

There's a simple formula : <em>sin θ = cos (90°- θ)</em> or <em>cos θ = sin (90°- θ) </em>

So : cos 0° = sin (90° - 0°) = sin 90° = 1


7 0
3 years ago
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