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rusak2 [61]
3 years ago
9

A rope is attached to a tent pole at a height of 3.5 feet above the ground. The rope connects to a point that is 6.8 feet from t

he bottom of the pole. To the nearest tenth of a foot, what is the length of the rope? 7.6 ft 1.2 ft 5.8 ft 4.5 ft

Mathematics
2 answers:
ipn [44]3 years ago
4 0
I'm sorry but I'm confused, Is the rope connected like A or B, if it's connected like the picture A then it's 5.8ft but if connected like B then it is 7.6ft

loris [4]3 years ago
4 0

Answer:

The length of the rope is 7.6 ft ( approx )

Step-by-step explanation:

Let, The line segment AB shows the length of the pole, ( where A is the top and B is the bottom ) and line segment AC shows the rope,

According to the question,

AB = 3.5 ft,

BC = 6.8 ft,

Since, the pole must be vertical with respect to the ground,

That is, ∠ABC = 90°,

Thus, by Pythagoras theorem,

AC² = AB² + BC²

⇒ AC² = 3.5² + 6.8² = 12.25 + 46.24 = 58.49,

⇒ AC = √ 58.49 = 7.64787552 ≈ 7.6 ft

Hence, the length of the rope is approximately 7.6 ft.

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A rectangular garden is 16 feet wide. Its length is 8 feet more than twice the width. What is the area of the garden?
marysya [2.9K]

Answer:

640 ft²

Step-by-step explanation:

Hi there!

We're given:

Width = 16

Length = 2 x Width + 8

Solve for the length:

l = 2(16)+8

l=32+8

l=40

Therefore, the length of the garden is 40 ft.

To find the area, multiply the length and width:

A = lw

A = (16)(40)

A = 640 ft²

I hope this helps!

5 0
3 years ago
The student council at a college is made up of four ​freshmen, five ​sophomores, six ​juniors, and seven seniors. A yearbook pho
asambeis [7]

Answer:

7257600

Step-by-step explanation:

Number of freshmen in the student council= 4

Number of sophomores in the student council= 5

Number of juniors in the student council= 6

Number of seniors in the student council= 7

Ways of choosing council members

⁴C₂×⁵C₂×⁶C₂×⁷C₂

^4C_2=\frac{4!}{(4-2)!2!}\\=\frac{24}{4}=6\\\\^5C_2=\frac{5!}{(5-2)!2!}\\=\frac{120}{12}=10\\\\^6C_2=\frac{6!}{(6-2)!2!}\\=\frac{720}{48}=15\\\\^7C_2=\frac{7!}{(7-2)!2!}\\=\frac{5040}{240}=21

⁴C₂×⁵C₂×⁶C₂×⁷C₂=6×10×15×21=18900

Ways of lining up the four classes=4!=1×2×3×4=24

Ways of lining up members of each class=2⁴=2×2×2×2=16

Pictures are possible if each group of classmates stands​ together

⁴C₂×⁵C₂×⁶C₂×⁷C₂×4!×2⁴

=18900×24×16

=7257600

7 0
3 years ago
There are 7 times as many males as females on the maths course at university. What fraction of the course are female?
Alinara [238K]

Answer:

1/8

Step-by-step explanation:

Suppose there are 7 males so there will be 1 female according to the question.

So there is 1 female out of a total of 8 students. So the answer is 1/8.

Because the female is 1 out of the 8 people.

3 0
2 years ago
Need help and ASAP again please
xenn [34]

Answer:

A=60

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
The formula for the perimeter of a rectangle is P=2(l+w). Solve for l.
Readme [11.4K]

Answer:

l = \frac{P-2w}{2}

Step-by-step explanation:

Given

P = 2(l + w) ← distribute right side

P = 2l + 2w ( subtract 2w from both sides )

P - 2w = 2l ( isolate l by dividing both sides by 2 )

\frac{P-2w}{2} = l

7 0
3 years ago
Read 2 more answers
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